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Dimas [21]
3 years ago
13

How far from 0 is -6

Mathematics
1 answer:
Finger [1]3 years ago
8 0
-6 numbers away from 0 hope this helped
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What is the equation of the lines that passes through the points (-2, -3) and (4, -5)?
antoniya [11.8K]
Since all the options are in the slope intercept form, we find the equation using the formula,

y = mx + c
We can find m, the slope using the formula,

m = \frac{ change \: in \: y }{change \: in \: x}
m = \frac{ - 5 - - 3}{4 - - 2}
m = \frac{ - 2}{6} = - \frac{1}{3}

On substitution,

y = - \frac{ 1}{3} x + c

We use any of the points, say (-2,-3) to determine the value of c.

- 3 = - \frac{1}{3} ( - 2) + c
c = - \frac{11}{3}

The equation is therefore,

y = - \frac{1}{3} x - \frac{11}{3}

The correct answer is D.
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=12%20%5Cfrac%7B1%7D%7B3%7D%20%5Cdiv%202" id="TexFormula1" title="12 \frac{1}{3} \div 2" alt="1
aev [14]

Answer:

37/6

Step-by-step explanation:

Simplify the following:

(12 + 1/3)/2

Put 12 + 1/3 over the common denominator 3. 12 + 1/3 = (3×12)/3 + 1/3:

((3×12)/3 + 1/3)/2

3×12 = 36:

(36/3 + 1/3)/2

36/3 + 1/3 = (36 + 1)/3:

((36 + 1)/3)/2

36 + 1 = 37:

(37/3)/2

37/3×1/2 = 37/(3×2):

37/(3×2)

3×2 = 6:

Answer: 37/6

3 0
3 years ago
1)2 out of 7 students are boys. about what percent of students are boys? please help me with the question it is due tomorrow!!!!
notka56 [123]
The long answer is <span>28.571428%, but I would round it upwards to make it seem more realistic.</span>
8 0
3 years ago
Use the digits 2,3,and 5 to create a fraction and a whole number with a product greater than 2
mylen [45]

Product is multiplication.

Since the answer needs to be greater than 2 either the fraction needs to be an improper fraction ( meaning the fraction would be greater than 1) or the whole number would need to be greater than 2.


One answer would be 5 x 2/3 = 3 1/3

3 0
3 years ago
 what is perpendicular to y= 3x -9 and passes through the point (3,1)
GREYUIT [131]
(3,1) , \ \ y= 3x -9 \\ \\ The \ slope \ is :m _{1} =3 \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \ m _{1} \cdot m _{2} = -1 \\ \\3\cdot m_{2}=-1 \ \ /:3\\ \\ m_{2}=-\frac{1}{3}

\Now \ your \ equation \ of \ line \ passing \ through \ (3,1) would \ be: \\ \\ y=m_{2}x+b \\ \\1=-\frac{1}{ 3} \cdot3 + b

1=-1+b\\ \\ b=1+1\\ \\b=2 \\ \\ y =- \frac{1}{3}x+2


6 0
3 years ago
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