15%=3
5%=1
5(20)=100
1(20)=20
So, there are 20 students in the class.
Answer:
b for me hehe ok
Step-by-step explanation:
Explanation
Answer:
<em>The perimeter is 72 units and the area is 149 square units.</em>
Step-by-step explanation:
has coordinates
and 
Using the distance formula.........
Length of side 
Length of side 
Length of side 
So, the perimeter of the triangle will be:
units. <em>(Rounded to the nearest unit)</em>
The height of the triangle for the corresponding base
is 8.89 units.
<u>Formula for the Area of triangle</u>, 
So, the area of the
will be:
square units. <em>(Rounded to the nearest unit)</em>
Convert all into a fraction and you will get 115/100+1/50+47/40
So your answer is 469/200 or 2.345 as a decimal
Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:

(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)