Answer: 100+1.28(1/2)=100.64
Step-by-step explanation:
A random sample of size 16 is to be taken from a normal population having mean 100 and variance 4. ... The 90th percentile of the normal curve, according to the table I was provided, was equal to 1.28 standard units above the mean.
Answer:
72
Step-by-step explanation:
