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3 years ago

Find the coordinates of the midpoint of the segment whose endpoints are H(2, 1) and K(10, 7)

2 answers:

7 0

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
H&({{ 2}}\quad ,&{{ 1}})\quad 
% (c,d)
K&({{ 10}}\quad ,&{{ 7}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)$

you tell us

Sunny_sXe [5.5K]3 years ago

3 0

Answer:

Find the coordinates of the midpoint of the segment whose endpoints are H(2, 1) and K(10, 7).

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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4 years ago

Read 2 more answers

Answer the questions below about the quadratic function.

Korolek [52]

Given the function $f(x)=3x^2-18x+23$ . The above function can be written as

$f(x)=3x^2-18x+23\\ f(x)=3(x^2-6x)+23\\ f(x)=3(x^2-6x+9-9)+23\\ f(x)=3(x-3)^2-27+23\\ f(x)=3(x-3)^2-4$

a)Now, the function $f(x)=3(x-3)^2-4$ has minimum value since the coefficient of $(x-3)^2$ is $3>0$ .

b) The minimum value of the function occurs at $x=3$ and its value is

$f(3)=3(3-3)^2-4 =-4$

c)The minimum value of the function occurs at $x=3$ .

6 0

3 years ago

24+28 written in distributive prop

AleksandrR [38]

Answer:

24 + 28

2*2*2*3 + 2*2*7 [prime factors]

You may distribute any common ones, for example:

4(6+7) [that is, 2*2*(2*3 + 7)

2(12+14)

Step-by-step explanation:

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3 years ago

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Which of the following best defines 3 to the power of 2 over 3?

Anika [276]

Answer:

Option B is correct that is cube root of 9.

Step-by-step explanation:

We have been given the expression:

$3^{\frac{2}{3}}$ after solving square power

It can be rewritten as $9^{\frac{1}{3}}$

Which is the cube root of 9

Hence, Option B is correct That is cube root of 9

Option A is discarded because square gets solve then only we get 9

Option C and D are discarded because square will be solve we will get 9.

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3 years ago

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Question 9 (1 point)

natka813 [3]

30.66pi ft³

First, we need to find the volume of the cylinder using the following equation

$V = r^2h\pi \\V = (2^2)5\pi \\V = (4)5\pi \\V = 20\pi$

The volume of the cylinder is 20pi

Next, we need to find the volume of a sphere. Since the cylinder is divided in half by the cylinder, we can use the following equation as if it were whole

$V = \frac{4}{3} r^3\pi \\V = \frac{4}{3} 2^3\pi \\V = \frac{4}{3} 8\pi \\V = 10\frac{2}{3} \pi$

The volume of both half spheres is 10.66pi

Now we can add both together to get 30.66pi ft³

7 0

3 years ago