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3 years ago

How to solve this question?

Mathematics

1 answer:

bagirrra123 [75]3 years ago

7 0

Answer:

-11.

Step-by-step explanation:

f(x) = √(3 - 2x), x ≤ 3/2

let y = √(3 - 2x)

y^2 = 3 - 2x

2x = 3 - y^2

x = (3 - y^2)/2

So f-1(x) = (3 - x^2)/2

f-1(x) = (3 - 5^2) / 2 = -11.

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According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago

What is the area of circle C when the radius is 0.4cm

Solnce55 [7]

I think it’s 0.5, sorry if it’s wrong

7 0

3 years ago

2. 2x+6y=6 -x-3y = -3 Solution(s): PLEASE HELP SOLVE FOR X AND Y

allochka39001 [22]

Answer:

x = 0, y = 1

Step-by-step explanation:

2x + 6y = 6 → (1)

x - 3y = - 3 ( add 3y to both sides )

x = 3y - 3 → (2)

substitute x = 3y - 3 into (1)

2(3y - 3) + 6y = 6 ← distribute parenthesis and simplify left side

6y - 6 + 6y = 6

12y - 6 = 6 ( add 6 to both sides )

12y = 12 ( divide both sides by 12 )

y = 1

substitute y = 1 into (2)

x = 3(1) - 3 = 3 - 3 = 0

solution is x = 0 , y = 1

3 0

2 years ago

Solve the inequality.

77julia77 [94]

42 < -6d

divide 6 by both sides,

7 < -d

6 0

3 years ago

**30 POINTS** The Scotts have a yard in the shape of a square. The area of the yard is 128 square meters, and the Scotts want to

miskamm [114]

Answer:

45.24m

Step-by-step explanation:

Area of square = s^2

128 = s^2

s^2 = 11.31m.

This is the length of ONE SIDE.

Squares have four sides.

Homeboy wants to place a fence bordering is entire yard. AKA four sides.

11.31*4= 45.24m

7 0

3 years ago