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3 years ago

How to solve this question?

Mathematics

1 answer:

bagirrra123 [75]3 years ago

7 0

Answer:

-11.

Step-by-step explanation:

f(x) = √(3 - 2x), x ≤ 3/2

let y = √(3 - 2x)

y^2 = 3 - 2x

2x = 3 - y^2

x = (3 - y^2)/2

So f-1(x) = (3 - x^2)/2

f-1(x) = (3 - 5^2) / 2 = -11.

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What is equivalent 2r+(t+r)2

ozzi

Answer:

2 (2r + t)

Step-by-step explanation:

2r + (t + r) × 2

➡️ 2r + 2 (t + r)

➡️ 2 (r + t + r)

➡️ 2 (2r + t)

3 0

3 years ago

1) Which two teams had the greatest point difference?

MrMuchimi

1) Which two teams had the greatest point difference?
Delta and Beta (85 - 25 = 60)

2) Which two teams had the least point difference?
Delta and Gamma (85 - 75 = 10)

3) What was the average score of the 5 teams?
(45+25+75+85+65) / 5 = 295 / 5 = 59

4) How many more points did Epsilon score than Beta?
Epsilon: 65
Beta: 25
65 - 25 = 40
Epsilon scored 40 more than Beta

5) Which teams scored more than 2 times Beta’s score?
twice of Beta = 25 x 2 = 50

answer
Gamma (75) , Delta (85) and Epsilon (65)

7 0

4 years ago

Ted needs an average of at least 70 on his three history tests. He has already scored 85 and 60 on two tests. What is the minimu

baherus [9]

He must get a 65 as a minimum grade on his third test to get an average of 70.
Equation is
85 + 60 + x
------------------- greater than or equal to 70
3

3 0

3 years ago

Help me out? :) don't guess, if u dont know just dont answer. NO LINKS.

avanturin [10]

Answer:

A cube

Step-by-step explanation:

If you fold it, you'll see

8 0

3 years ago

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0

3 years ago