Answer:
Option C. is correct
Step-by-step explanation:
In the triangle ABC, vertices are A(12, 8), B(4, 8) and C(4, 14)
AB =
BC =
AC =
In triangle XYZ vertices are X(6,6), Y(4,12) and Z(10, 14)
XY =
YZ =
XZ =
In triangle MNO, vertices are M(4, 16), N(4, 8) and O(-2, 8)
MN =
MO =
NO =
In triangle JKL, vertices are J(14, -2), K(12,2) and L(20, 4)
JK =
KL =
JL =
Now we compare the sides for the congruence
Since AB = MN = 8
BC = NO = 6
AC = OM = 10
So ΔABC ≅ Δ MNO
Option C. is correct
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