Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
The answer is C), 834, 834.19, 834.2, 834.29
I know this is late, but I hope it was helpful!
True, because if you add pi (3.14) to 0, you get the result 34.234, which is also the result of the formula which is used to shrink the dilation AND the pre-image.
It would be 2,000. 1,873 rounded to the next number is 2,000, if the number was 1,499 you would round down but since the second number is higher than 5 you round up no matter what
