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3 years ago

Solve 2(x + 1) = 2x + 2. (1 point) ♡ 0 O All real numbers No solution 1

Mathematics

1 answer:

sattari [20]3 years ago

6 0

Answer:

B. All real numbers

Step-by-step explanation:

2(x + 1) = 2x + 2

Distribute the 2 inside the parenthesis.

2x + 2 = 2x + 2

Since the two expressions are equal and will stay equal with any value, the answer to this question is All real numbers.

Example:

2(x + 1) = 2x + 2

2(5 + 1) = 2(5) + 2

2(6) = 10 + 2

12 = 12

2(x + 1) = 2x + 2

2(150 + 1) = 2(150) + 2

2(151) = 300 + 2

302 = 302

The expression is equal for any value put in x.

You might be interested in

Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. H

Sergeeva-Olga [200]

Answer:

The answer is b. But you asked for the thought process so...

Step-by-step explanation:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, the time taken to cover a distance of 50 miles on his first trip = 50/x hr.

And the time taken to cover a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: twice as much.

Have a great day :)

4 0

3 years ago

1/2 of a bag of candy is skittles, 1/4 is m and m's, and 3/4 of the rest of it are life savers. The rest are sour patch kids. Wh

m_a_m_a [10]

Answer:

6.25%

Step-by-step explanation:

Total = 1 ; as a decimal

1/2 = skittles

1/4 = M&Ms

Skittles +M&Ms = 1/2 + 1/4 = 3/4

Remainder = 1 - $\frac{3}{4}$

Remainder = $\frac{1}{4}$

Sour patch = $\frac{1}{4} *\frac{1}{4} =\frac{1}{16}$

As a percentage , multiply 1/16 by 100 and it becomes 6.25%

5 0

3 years ago

Use the Counting Principle to find the probability. Choosing the 7 winning lottery numbers when the numbers are chosen at random

frozen [14]

Answer: 120

<u>Step-by-step explanation:</u>

Since the order of the numbers doesn't matter we can use the formula:

$\dfrac{n!}{r!(n-r)!}\quad \text{where n is the quantity of items and r is the quantity chosen}\\\\\text{In this problem, there are 10 numbers (n = 10) and 7 to be chosen (r = 7)}\\\\_{10}C_{7}=\dfrac{10!}{7!(10-7)!}\\\\.\qquad=\dfrac{10!}{7!3!}\\\\.\qquad=\dfrac{10\times 9\times 8\times 7!}{7!\times 3\times 2\times 1}\\\\.\qquad=10\times 3\times 4\\\\.\qquad=120$