Answer:
you have to create an account which should be pretty easy to find and just use your personal email!
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
![\frac{20{x}^{2} {y}^{5} }{12x {y}^{7} } = \frac{ 5x}{3 {y}^{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B20%7Bx%7D%5E%7B2%7D%20%20%7By%7D%5E%7B5%7D%20%7D%7B12x%20%7By%7D%5E%7B7%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%205x%7D%7B3%20%7By%7D%5E%7B2%7D%20%7D%20)
Notice the picture below
![\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center\ ({{ h}},{{ k}})\qquad radius={{ r}}\\\\ -----------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 1}}\quad ,&{{ 4}})\quad % (c,d) &({{ 4}}\quad ,&{{ 8}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\leftarrow r](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%0A%28x-%7B%7B%20h%7D%7D%29%5E2%2B%28y-%7B%7B%20k%7D%7D%29%5E2%3D%7B%7B%20r%7D%7D%5E2%0A%5Cqquad%20center%5C%20%28%7B%7B%20h%7D%7D%2C%7B%7B%20k%7D%7D%29%5Cqquad%0Aradius%3D%7B%7B%20r%7D%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%28%7B%7B%201%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0A%26%28%7B%7B%204%7D%7D%5Cquad%20%2C%26%7B%7B%208%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%5Cleftarrow%20r)
you have the center, the h,k, all you really need is the radius "r"
Answer:
a) 3 x 20 = 60
b) -2x20 = -40
question c and d are unclear as we do not know how many questions were wrong and how many were not answered.
Sorry but I hope that helped
HEY if you remove it you will get a curse