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3 years ago

2100 +809 equals ?????

Mathematics

2 answers:

lord [1]3 years ago

6 0

2100 + 809 equals to 2909.

Naddika [18.5K]3 years ago

5 0

2100
+809
--------
2909

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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12 a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

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2 years ago

If f(x) = 2x + 3 and g(x) = x^2 + 1,find f(g(3)). A.) 23 B.) 47 C.) 82 D.) 90

marta [7]

The answer is A). 23.
g(x)= 2x + 3 
g(x) = x^2 + 1 
g(3) = 10 
f(g(3)) 
= f(10) 
= 23

6 0

3 years ago

If you were to roll the dice one time, what is the probability it will land on a 2?

vladimir2022 [97]

Answer:

1 out of 6

Step-by-step explanation:

6 0

3 years ago

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Find x.______________a0

velikii [3]

Answer:

$x=4$

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

$\frac{2}{y}=\frac{y}{6}$

$y^2=12$

$y=\sqrt{12}$

$y=2\sqrt{3}$

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

$a^2+b^2=c^2$

$2^2+(2\sqrt{3})^2=c^2$

$4+12=c^2$

$c^2=16$

$c=4$

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

$x=4$

4 0

2 years ago

128 is the product of hectors score and 8 Fastest answer will be the brainliest

Inga [223]

Answer:

The equation would be 8h= 128

Step-by-step explanation:

7 0

2 years ago

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