I think it's B. The Start menu.
Answer:
1.trees_destroyed_per_hectare = 456/2.47
2. input(no_of_hectares)
3. no_of_trees_destroyed =no_of_hectares * trees_destroyed_per_hectare
4. print(no_of_trees_destroyed)
Explanation:
1.trees_destroyed_per_hectare = 456/2.47 //conversion of tress destroyed per acres to hectare
2. input(no_of_hectares) // get input from user in hectares that how many hectares are destroyed
3. no_of_trees_destroyed =no_of_hectares * trees_destroyed_per_hectare // total number of trees destroyed by fire on given day and given area
4. print(no_of_trees_destroyed)
Answer:
Answer: Program to estimate the power spectral density of the signal
Explanation:
fs= 4000; % Hz sample rate Ts= 1/fs; f0= 500; % Hz sine frequency A= sqrt(2); % V sine amplitude for P= 1 W into 1 ohm. N= 1024; % number of time samples n= 0:N-1; % time index x= A*sin(2*pi*f0*n*Ts) + .1*randn(1,N); % 1 W sinewave + noise
Spectrum in dBW/Hz
nfft= N; window= rectwin(nfft); [pxx,f]= pwelch(x,window,0,nfft,fs); % W/Hz power spectral density PdB_Hz= 10*log10(pxx); % dBW/Hz
Spectrum in dBW/bin
nfft= N; window= rectwin(nfft); [pxx,f]= pwelch(x,window,0,nfft,fs); % W/Hz power spectral density PdB_bin= 10*log10(pxx*fs/nfft); % dBW/bin
Cpu...................................
Answer:
The answer is below
Explanation:
Given that the three-point lighting techniques require one to have three sources of lights in a scene. These three lights are known as Back light, key light, and fill light.
The Back light is expected to be placed at the back of the subject. In this scenario, there is a lit fireplace behind the subject, this is serving as the backlight already.
The glow from a window on the subject's left is serving as a Fill light which is not going to be bright as that of the Key lights.
Then Laura would now only need the Key Light. This will be the main light and will be the brightest. Laura will have to place this Key Light on the right side of the subject on the scene, directly at the opposite of the glowing light serving as the Fill light.
