Answer:
b.Make every attempt to recover the data
Explanation:
If you have important data on your hard drive that is not backed up and your Windows installation is so corrupted you know that you must refresh the entire installation you should make every attempt to recover the data.
spec sheet is a document that summarizes the performance and other technical characteristics of a product, machine or component.
Answer:
1.word = "George slew the dragon"
startIndex = word.find('dr')
endIndex = startIndex + 4
drWord = word[startIndex:endIndex]
2. sentence = "Broccoli is delicious."
sentence_list = sentence.split(" ")
firstWord = sentence_list[0]
Explanation:
The above snippet is written in Python 3.
1. word is initialized to a sentence.
Then we find the the occurence of 'dr' in the sentence which is assign to startIndex
We then add 4 to the startIndex and assign it to endIndex. 4 is added because we need a length of 4
We then use string slicing method to create a substring from the startIndex to endIndex which is assigned to drWord.
2. A string is assigned to sentence. Then we split the sentence using sentence.split(" "). We split based on the spacing. The inbuilt function of split returns a list. The first element in the list is assigned to firstWord. List uses zero based index counting. So. firstWord = sentence_list[0] is use to get first element.
Answer:b) The computer program that processes the data.
Explanation: In the computer system , process is the part of computer program which are responsible for performing of the processing of the data and other functions .The working of the process is associated with the program code and related activities/functions.
Other options that are mentioned in the question are incorrect because they don't describe the process correctly .Thus , the correct answer is option (b).
Program p1;
var a,b,c,d : integer; {i presume you give integer numbers for the values of a, b, c }
x1, x2 : real;
begin
write('a='); readln(a);
write('b='); readln(b);
write('c=');readln(c);
d:=b*b - 4*a*c
if a=0 then x1=x2= - c/b
else
if d>0 then begin
x1:=(-b+sqrt(d)) / (2*a);
x2:=(-b - sqrt(d))/(2*a);
end;
else if d=0 then x1=x2= - b /(2*a)
else write ("no specific solution because d<0");
writeln('x1=', x1);
writeln('x2=',x2);
readln;
end.
