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makvit [3.9K]
3 years ago
15

Laura is filming a scene in which the subject is sitting with a lit fireplace behind him. The only other source of light in the

room is the glow from a window on the subject's left. How should Laura set up a standard three-point lighting system for the shot?
Computers and Technology
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

The answer is below

Explanation:

Given that the three-point lighting techniques require one to have three sources of lights in a scene. These three lights are known as Back light, key light, and fill light.

The Back light is expected to be placed at the back of the subject. In this scenario, there is a lit fireplace behind the subject, this is serving as the backlight already.

The glow from a window on the subject's left is serving as a Fill light which is not going to be bright as that of the Key lights.

Then Laura would now only need the Key Light. This will be the main light and will be the brightest. Laura will have to place this Key Light on the right side of the subject on the scene, directly at the opposite of the glowing light serving as the Fill light.

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It is either an internal IP address or it is a private IP address.

Explanation:

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What is garbage in garbage out?​
Neko [114]

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2 years ago
Pass the two arrays to a method that will display the integer value(s), if any, that appear in both arrays (note that the two ar
vampirchik [111]

Answer:

The solution code is written in Java

  1.    public static void checkCommonValues(int arr1[], int arr2[]){
  2.        if(arr1.length < arr2.length){
  3.            for(int i = 0; i < arr1.length; i++){
  4.                for(int j = 0; j < arr2.length; j++){
  5.                    if(arr1[i] == arr2[j]){
  6.                        System.out.print(arr1[i] + " ");
  7.                    }
  8.                }
  9.            }
  10.        }
  11.        else{
  12.            for(int i = 0; i < arr2.length; i++){
  13.                for(int j = 0; j < arr1.length; j++){
  14.                    if(arr2[i] == arr1[j]){
  15.                        System.out.print(arr2[i] + " ");
  16.                    }
  17.                }
  18.            }
  19.        }
  20.    }

Explanation:

The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.

Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).

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2 years ago
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