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butalik [34]
3 years ago
9

If 24 - 2x = 19 + 3x, then x =

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

1 =x

Step-by-step explanation:

24 - 2x = 19 + 3x

Add 2x to each side

24 - 2x+2x = 19 + 3x+2x

24 = 19 +5x

Subtract 19 from each side

24-19 =19+5x-19

5 = 5x

Divide by 5

5/5 = 5x/5

1 =x

Kipish [7]3 years ago
5 0

\longrightarrow{\green{  \: x = 1  }} 

\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}

24 - 2x = 19 + 3x

Combine like terms,

➺ \: 3x + 2x = 24 - 19

➺ \: 5x = 5

➺ \: x =  \frac{5}{5}

➺ \: x = 1

\sf \bf {\boxed {\mathbb {To\:verify:}}}

➼ 24 - 2 \times 1 = 1 9+ 3 \times 1

➼ \: 24 - 2 = 19  + 3

➼ \: 22 = 22

➼ \: L.H.S.=R. H. S

Hence verified.

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822772

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
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Integrate it by applying the power rule:

\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
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\mathsf{=-\,\dfrac{1}{u}+C}


Now, substitute back for u = sin x, so the result is given in terms of x:

\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}


\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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