Answer:
Part a) The approximate years were 1998 and 2008
Part b) The graph in the attached figure
Step-by-step explanation:
Part a) we have

For
Solve the quadratic equation


we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have

so
substitute in the formula
therefore
The approximate years are
1997+11=2008
1997+1=1998
Part b)
Using a graphing tool
we have


The solution of the system of equations is the intersection point both graphs
The intersection point are (0.99,80) and (11.23,80)
see the attached figure
therefore
The solution part a) is correct
Answer: y = lxl + 5. B) y = 1. 2 x + 3. C) y = x2 - 4. D) y = 3. 4 x2. Explanation: The solution ... y = x. B) y = |x|. C) y = x2. D) y = x. Explanation: A linear function has a degree of 1. ... 2. 4. B. x f(x). 1. 6. 2. 7. 3. 8. 4. 9. 5 10. C. x f(x). -2 -3. -1 -1. 0. 1. 1. 3. 2. 5. D. ... Since the x is cubed in y = −3x3, it graphs as a curve. y = 5 ...
Step-by-step explanation:
Answer:y=4x+6
Step-by-step explanation:
We have the information that the slope is 4 and the line goes through the point (-2,-2). With this information, we can make a linear equation in a point slope form (
, so the equation would be
, or simplified,
in order to solve for y (to make it a slope-intercept equation), we must subtract 2 from both sides. This gives us the equation y=4x+6. Hope this helps!
Answer: $4.40
Step-by-step explanation:
Trust me did the assignment
Pythagorean theorem
c2 = a2 + b2
71^2 = 43^2 + b2
5041 = 1849 + b2
3192 = b2
b = 56.5 which is answer choice d