C ; 12 i think
or
B ; 144
I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
Answer:
3.2
Step-by-step explanation:
Given the coordinates
X(4, -3)
Y(2, 1.5)
A(3, 3)
Z(4,-1)
We are to find the distance from point A to XZ
First let us get the coordinate XZ
According to vector notation XZ = Z-X
XZ = (4,-1)-(4,-3)
XZ = [(4-4),-1-(-3)]
XZ = (0, 2)
Next is to find the distance from A(3, 3) to XZ(0,2) using the formula for calculating the distance between two points.
D = √(x2-x1)²+(y2-y1)²
x1 = 3, y1 = 3, x2 = 0, y2 = 2
D = √(0-3)²+(2-3)²
D = √9+1
D = √10
D = 3.16
Hence the distance from point A to XZ to nearest tenth is 3.2
Answer:
x=1
y=2
Step-by-step explanation:
Answer:
1, 3 and 5.
Step-by-step explanation:
