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Stolb23 [73]
3 years ago
14

Find xtriangle 2x+25, 7x+20, and 4x+20

Mathematics
1 answer:
Fantom [35]3 years ago
4 0
Total measure of the triangle is 180
So you set the equation equal to 180 and then solve for x using basic calculation

13x=115
X=8,85
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A,64.25+35.25+25
emmasim [6.3K]

Answer:

I don't really understand but Hope's this helps

Step-by-step explanation:

what is the question

8 0
3 years ago
A central angle in a circle with a radius of 3cm intercepts an arc with a length of 6cm. What is the radian measure of the centr
Nesterboy [21]
The correct answer for the question that is being presented above is this one: 

Radian Measure can be acquired by using the formula
Radian Measure = arc length / radius
Radian Measure = 6 cm / 3 cm
Radian Measure = 2 rad.
4 0
3 years ago
A bus travels 20 km in 30 minutes. What is the average speed of the<br> bus in km/hr?
sergeinik [125]

Answer:

40 km

Step-by-step explanation:

You have 2 variables: km and minutes/hour

30 minutes turned into 60 minutes(1 hour) by multiplying by 2...

So you need to do the same for km!

20km * 2 = 40km per hour

8 0
3 years ago
Which among the following is the largest rational number? -2/4 -2/3 -1/3 -4/5
nadezda [96]

Answer:

-1/3

Step-by-step explanation:

All of the other numbers are less than -1/3

3 0
4 years ago
Read 2 more answers
A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

4 0
3 years ago
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