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pickupchik [31]
4 years ago
5

Find all real numbers x such that 3x - 4 < 5 and -8x - 19 < 21

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
6 0

Answer:

3x<5+4

=3x<9

=x<<u>9</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>3

x<3

-8x-19<21

-8x<21+19

-8x<40

x<<u>4</u><u>0</u>

<u> </u><u> </u><u> </u><u> </u><u>-</u><u>8</u>

x<-5

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svetlana [45]

Answer:

A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.

B: The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots.

Step-by-step explanation:

f(x) = 12x^2 + 5x - 2.

Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).

To find the roots of f(x), set f(x) = 0. Therefore:

12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:

12x^2 + 8x - 3x - 2 = 0.

4x(3x + 2) -1(3x+2) = 0.

(4x-1)(3x+2) = 0.

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It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!

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And the last one, they are both simply positive.

Hope this helps <3

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