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nasty-shy [4]
3 years ago
7

Help me

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

C

Step-by-step explanation:

It is the only answer where the negative signs do not even out on both sides of the equation.

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A middle school took all of its 6th grade students on a field trip to see a symphony. The students filled 300 seats, which was 1
prisoha [69]

Answer:

3,000

Step-by-step explanation:

Basically, there are 300 seats filled which is 10%

100% is 10x10

300=10%

multiply both sides by 10

300x10=3000 and 10x10=100

therefore, the total number of seats is 3000 since 100% represents the whole thing.

Hope this was helpful!

5 0
3 years ago
Hey someone who knows this want to give me the answer thanks
Gnesinka [82]
C is the answer. Hope this helps!
4 0
3 years ago
Read 2 more answers
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
(2x +1) -7 (-6x+9) what is the answer if using the Distributive Property?
Margarita [4]

Answer:

Step-by-step explanation:

Distributive property:  a(b +c) = a*b + a*c

(2x + 1) - 7(-6x + 9) = (2x + 1) + (-7)*(-6x) + (-7)*9

                              = 2x + 1 + 42x - 63  {Combine like terms}

                              = 2x + 42x + 1 - 63

                              = 44x - 62

5 0
3 years ago
Help me please it’s due by today
anyanavicka [17]

Answer:

D

Step-by-step explanation:

Lateral SA = area of the 4 triangles

Formula to be used :-

Area (triangle) = 1/2bh

=> 4 x 1/2 x 9 x 12

=> 108 x 2

=> 216 cm²

Total SA = LSA + area of the square

Formula to be used :-

Area (square) = side length x side length

=> 216 + 9 x 9

=> 216 + 81

=> 297 cm²

<u>The correct option is (D).</u>

4 0
3 years ago
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