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2 years ago

Find the second of two consecutive integers if the second is 13 less than twice the first.

1 answer:

4 0

What is the range in which the integers can be in? I cannot fully answer this question. But I think there could be more than one answer. One answer would be the first is 36 and the second is 66.

Hope this helps!
Can u plz mark me as brainliest? I really need it!

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Look at the figure and answer

andreyandreev [35.5K]

Answer:

$\cos x=\dfrac{8}{f}$

Step-by-step explanation:

Given that,

$\tan x=\dfrac{e}{8}\\\\\sin x=\dfrac{e}{f}$

We need to find the value of cos x.

We know that,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

Using the above relation,

$\dfrac{e}{8}=\dfrac{\dfrac{e}{f}}{\cos x}\\\\\cos x=\dfrac{\dfrac{e}{f}}{\dfrac{e}{8}}\\\\=\dfrac{e}{f}\times \dfrac{8}{e}\\\\=\dfrac{8}{f}$

So, the value of cos x is equal to $\dfrac{8}{f}$ .

7 0

3 years ago

Pls helpppppp I really need helpppp

dem82 [27]

A and c are true ! I hope this helps

8 0

2 years ago

Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)] and select the correct answer below.

Alexxx [7]

The answer is 3x-39 please tell the no wrong

8 0

3 years ago

Read 2 more answers

Can you please help me?

garri49 [273]

Answer:

6.2

Step-by-step explanation:

$\frac{10.3}{sin(90)} = \frac{x}{sin(37)}$ *Cross multiply*

10.3(sin(37)) = x(sin(90)) *Divide by sin(90) to isolate x*

$x = \frac{10.3(sin(37))}{sin(90)}$ *Solve*

x = 6.19 ≈ 6.2

4 0

3 years ago

A data set lists earthquake depths. The summary statistics are nequals300, x overbarequals5.89 km, sequals4.44 km. Use a 0.01

kirza4 [7]

Answer:

Null hypothesis $H_0:\mu=5.00km$

Alternative hypothesis $H_1:\mu\neq 5.00km$

The p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

Step-by-step explanation:

It is given that a data set lists earthquake depths. The summary statistics are

$n=300$

$\overline{x}=5.89km$

$s=4.44km$

Level of significance = 0.01

We need to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 5.00.

Null hypothesis $H_0:\mu=5.00km$

Alternative hypothesis $H_1:\mu\neq 5.00km$

The formula for z-value is

$z=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}$

$z=\frac{5.89-5.00}{\frac{4.44}{\sqrt{300}}}$

$z=\frac{0.89}{0.25634351952}$

$z=3.4719$

The p-value for z=3.4719 is 0.000517.

Since the p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

6 0

3 years ago