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aivan3 [116]
2 years ago
13

Find the second of two consecutive integers if the second is 13 less than twice the first.

Mathematics
1 answer:
emmasim [6.3K]2 years ago
4 0
What is the range in which the integers can be in? I cannot fully answer this question. But I think there could be more than one answer. One answer would be the first is 36 and the second is 66.

Hope this helps!
Can u plz mark me as brainliest? I really need it!
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Look at the figure and answer
andreyandreev [35.5K]

Answer:

\cos x=\dfrac{8}{f}

Step-by-step explanation:

Given that,

\tan x=\dfrac{e}{8}\\\\\sin x=\dfrac{e}{f}

We need to find the value of cos x.

We know that,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

Using the above relation,

\dfrac{e}{8}=\dfrac{\dfrac{e}{f}}{\cos x}\\\\\cos x=\dfrac{\dfrac{e}{f}}{\dfrac{e}{8}}\\\\=\dfrac{e}{f}\times \dfrac{8}{e}\\\\=\dfrac{8}{f}

So, the value of cos x is equal to \dfrac{8}{f}.

7 0
3 years ago
Pls helpppppp I really need helpppp
dem82 [27]
A and c are true ! I hope this helps
8 0
2 years ago
Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)] and select the correct answer below.
Alexxx [7]
The answer is 3x-39 please tell the no wrong

8 0
3 years ago
Read 2 more answers
Can you please help me?
garri49 [273]

Answer:

6.2

Step-by-step explanation:

\frac{10.3}{sin(90)} = \frac{x}{sin(37)}                 *Cross multiply*

10.3(sin(37)) = x(sin(90))   *Divide by sin(90) to isolate x*

x = \frac{10.3(sin(37))}{sin(90)}                  *Solve*

x = 6.19 ≈ 6.2

4 0
3 years ago
A data set lists earthquake depths. The summary statistics are nequals300​, x overbarequals5.89 ​km, sequals4.44 km. Use a 0.01
kirza4 [7]

Answer:

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

Step-by-step explanation:

It is given that a data set lists earthquake depths. The summary statistics are

n=300

\overline{x}=5.89km

s=4.44km

Level of significance = 0.01

We need to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 5.00.

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The formula for z-value is

z=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}

z=\frac{5.89-5.00}{\frac{4.44}{\sqrt{300}}}

z=\frac{0.89}{0.25634351952}

z=3.4719

The p-value for z=3.4719 is 0.000517.

Since the p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

6 0
2 years ago
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