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Norma-Jean [14]
3 years ago
10

BRANILISTTTTthe attachment below is my question

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

the second one

Step-by-step explanation:

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Lim x -> infinity ((e^(3x)) - (e^(-3x)))/( (e^(3x)) + (e^(-3x)))
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When x<span> approaches to </span><span>+∞</span><span> the function </span><span>e^<span>3x</span></span><span> becomes much bigger then </span><span>e^<span>−3x</span></span><span>, which obviously means that </span><span>e^<span>−3x</span></span><span> can be neglected in both numerator and denominator.
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Here's how I figured this out: 

</span><span>lim <span>x →+∞ </span></span>= (<span><span><span>e^(<span>3x))</span></span>− (<span>e^(<span>−3x)) / (</span></span></span><span><span>e^<span>3x)) </span></span>+ (<span>e^(<span>−3x)) </span></span></span></span>= <span>lim <span>x → +∞ </span></span><span><span>e^<span>3x / </span></span><span>e^<span>3x </span></span></span>= 1
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