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3 years ago

6

Lamont works for an electric utility and is installing a 40 foot utility pole as shown. Lamont drills the anchor of a support ca

ble into the ground 15 feet from the base of the pole. What is the minimum length of cable Lamont needs?

1 answer:

otez555 [7]3 years ago

4 0

Kindy Refer to your text book!

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Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

Help please <br><br> hekfkdnr

mamaluj [8]

Answer:

first one is -16

second is -4

I'm what the third is

5 0

2 years ago

-5 can be thought of as "the opposite of 5". TRUE or FALSE

kap26 [50]

Answer:

True

Step-by-step explanation:

8 0

2 years ago

Please help me i need to complete this by tomorrow

lisov135 [29]

Answer:

Step-by-step explanation: Need to work out your scale factor which is 1.5.

8 * 1.5 = 12

CE = 12

12 * 9 = 108/2 = 59 that is the area of triangle ACE

8 * 6 = 48/2 = 24 that is the area of triangle BCD

ACE - BCD = ABDE

59 - 24 = 35cm^2

8 0

2 years ago

Write a linear equation that is parallel to

san4es73 [151]

Answer:

2y=11 - 5x

Step-by-step explanation:

An equation that is parallel shares the same gradient thus

2y= -5x - 8

y = -5/2x- 4

gradient m = -5/2

substitute value of m and the co-ordinates into a new linear equation

y = mx + c

-9 = (-5/2)(8) + c

c = 20-9 = 11

thus y = -5/2x + 11

2y=11 - 5x

5 0

2 years ago