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avanturin [10]
3 years ago
6

Lamont works for an electric utility and is installing a 40 foot utility pole as shown. Lamont drills the anchor of a support ca

ble into the ground 15 feet from the base of the pole. What is the minimum length of cable Lamont needs?
Mathematics
1 answer:
otez555 [7]3 years ago
4 0
Kindy Refer to your text book!
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The graphs of quadrilateral LMNO and its image are shown below.
REY [17]
You can use the ordered pairs to describe the translation that took place.

If you choose any vertex, you can use that to describe the translation that occurred with all vertices.

I'll look at N. Vertex N moved to the right 5 and up 7.

You can use the beginning and ending ordered pairs to see these distances.

Start: (-1, -1)
End: (4, 6)

-1 to 4 is 5 units
-1 to 6 is 7 units
6 0
3 years ago
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Lavonne sold 4 times as many raffle tickets as kenneth. lavonne sold 56 raffle tickets. how many tickets did kenneth sell?
bonufazy [111]

56÷4=14

Kenneth sold 14 tickets 
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4 years ago
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The amounts spent at a gift shop today are $19,$30,$28,$22,$26,and $26. What is the median and lower quartile?
GenaCL600 [577]

Answer:

Step-by-step explanation:

The lower cortile is 19 because that's the lowest number and the medium cortile is 24 because it's in the middle.

8 0
3 years ago
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Which of the binomials below is a factor of this trinomial? 4x2 + 12x + 9A. 2x-3B. 2x-1C. 2x+1D. 2x+3
katrin [286]

In order to factorate the trinomial, let's first find its roots using the quadratic formula:

\begin{gathered} b^2-4ac=12^2-4\cdot4\cdot9=144-144=0 \\ x_1=x_2=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}=\frac{-12+0}{2\cdot4}=-\frac{12}{8}=-\frac{3}{2} \end{gathered}

Now we can write the trinomial in the form:

a(x-x_1)(x-x_2)

So we have that:

4x2+12x+9=4(x+\frac{3}{2})(x+\frac{3}{2})=(2x+3)(2x+3)

So 2x + 3 is a factor of the trinomial, therefore the answer is D.

8 0
2 years ago
Find the volume and surface area
kompoz [17]

\bf \begin{array}{llll} \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}\\\\ V=\pi (8)^2(3)\\\\ V=192\pi \\\\ V\approx 603.19 \end{array}~\hfill \begin{array}{llll} \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=8\\ h=3 \end{cases} \end{array}~\hfill \begin{array}{llll} \stackrel{\textit{surface area of a cylinder}}{SA=2\pi r(h+r)}\\\\ SA=2\pi (8)(3+8)\\\\ SA=16\pi (11)\\\\ SA=176\pi \\\\ SA\approx 552.92 \end{array}

7 0
3 years ago
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