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IRINA_888 [86]
3 years ago
11

3. Find the number which is 32,586 more than 87,65,432.

Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

3. 8,798,018

4. 4,782,125

5. 156,432,332

6. 4,581,865

7. 4,594,375

8. 3,672,050

9. 7,272,925

10. 3,979,150

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Help me please!! please help!​
Yuki888 [10]

Answer:

1. 7:20hrs round to 7 hours (1 hour =60 minuite, and 20 is less than half of 60)

2. All numbers when divide by 1 is equal to itself (you can try with any number)

3. 9365<9635

the the second digit of 9635 is 6

the the second digit of 9365 is 3

Thus 9635 is greater

Brainliest please~

7 0
3 years ago
On anne's bicycle, the ratio of pedal turns to rear-wheel turns in second gear is 4 to 7. if her rear wheel turns 875 times per
quester [9]
Let the number of times she turns the pedal in one mile be x.

Given that her rear miles turns 875 times in one mile and the ratio of pedal turns to rear wheel turns is 4 to 7, then

\frac{4}{7} = \frac{x}{875}  \\  \\ \Rightarrow 7x=4(875)=3,500 \\  \\ \Rightarrow x= \frac{3,500}{7} =\bold{500}

Therefore, she turns the pedal 500 times in one mile.
8 0
3 years ago
Read 2 more answers
What is the area of this triangle
Sergeu [11.5K]
6 squared units

Hope this helps!

oh and here is the formula and substatution..
A=(b*h)/2
A=(6*2)/2
4 0
3 years ago
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 27 pi feet cubed. A sphere with height h
ioda

Answer:

C

Step-by-step explanation:

its not A for sure B and D dont make sense

3 0
3 years ago
Read 2 more answers
A company produces a certain product, and each unit of this product may have 3 different types of defects. Let Di, D2,Ds represe
Stella [2.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) 0.88

b) 0.02

c) 0.01

d) 0.99

Step-by-step explanation:

Step one: State the given parameters

            P(D_{1} ) = 0.12                                   P(D_{2} ) = 0.07

           P(D_{3} ) = 0.05                                    P (D_{1} U D_{2} ) = 0.13

          P(D_{1}n D_{2}n D_{3}) = 0.01                        P(D_{1} U D_{3}) = 0.14

Step 2 : Obtain the probability that a unit does not have a type 1 defect

         P(\frac{}{D_{1} }) =  1 -P(D_{1} )

                    = 1 - 0.12

                    = 0.88  

Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?

          The probability of the unit having both type 2 and type 3 defect is denoted as P(D_{2} n D_{3} )

   This is calculated as

                    P(D_{2}n D_{3}) =P(D_{2} ) + P(D_{3}) - P(D_{2} U D_{3})\\\\                          = 0.07 + 0,05 - 0.13

                    =   0.02

Therefore P(D_{2} n D_{3} ) = 0.02

Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect

                  Let P(\frac{}{D_{1}} n D_{2} n D_{3} ) denote the  probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.

This can be calculated as follows :

                      P(\frac{}{D_{1}} n D_{2} n D_{3} ) = P(D_{2} n D_{3}) - P(D_{1} n D_{2}nD_{3})

                                               =   0.02 - 0.01

                                               =  0.01

Step 4 : Obtain the probability that a unit has at most two defects

               P(at most 2 defects)  = 1 - P(all three defects)

                                                  = 1- P(D_{1} n D_{2}nD_{3})

                                                  =  1 - 0.01

                                                  = 0.99

7 0
3 years ago
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