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3 years ago

Urgent, please i will give brainliest

Mathematics

2 answers:

Drupady [299]3 years ago

7 0

Answer:

1). First option √13/3

2). Third option 3.2362

3). Third option 60/11

Step-by-step explanation:

1). To find cosec θ

It is given cot θ = 2/3

We have cotθ = adjacent side /Opposite side

Hypotenuse = √(adjacent side² + opposite side²) =√(2² + 3²) = √13

Cosec θ = Hypotenuse/opposite side = √13/3

2). To find cosec θ 

It is given that,

Sinθ = 0.3090

Cosec θ = 1/Sinθ = 1/0.3090 = 3.2362

3). To find cot θ

It is given that,

Tanθ = 11/60

Cot θ = 1/tan θ = 1/(11/60) = 60/11

Ne4ueva [31]3 years ago

3 0

Answer:

1. $\frac{\sqrt{13} }{3}$

2. 3.2362

3. $\frac{60}{11}$

Step-by-step explanation:

Cot is the trigonometric ratio defined by "adjacent" over "opposite". So, adjacent = 2 and opposite = 3.

By pythagorean theorem, we have the "hypotenuse" as $\sqrt{2^2+3^2}=\sqrt{13}$

Csc is defined as the trig ratio "hypotenuse" over "opposite". We know the sides, so Csc $\theta$ = $\frac{\sqrt{13} }{3}$

First answer choice is right.

By definition, Csc $\theta$ is the inverse of Sine $\theta$ . If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:

$Csc\theta=\frac{1}{0.3090}\\=3.2362$

Third answer choice is right.

By definition tan and cot are inverse of each other. So the value of tan is the reciprocal of the value of cot. We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

$Cot\theta=\frac{60}{11}$

Third answer is right.

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2 years ago

A stadium has 50,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in Sect

Pepsi [2]

Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

28A+24B+20C=1,258,000 (2)

A=B+C (3)

A= number of seats in section A

B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

B=(50,000/2)-(2C/2)

B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

42,000=4C

C=42,000/4

C=10,500

Now, you can replace the value of C in B=25,000-C:

B=25,000-10,500

B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

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Answer:

Step-by-step explanation:

Money spent on rent =1/3 of $576= 1/3×576= $192

Money spent on food = 1/4 of 576 = 1/4×576 =$144

Money left = 576-(192+144)=

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3 years ago

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----------------------------------------

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