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Andreas93 [3]
2 years ago
11

Insert a monomial so that each result is an identity( *− 3b4)(3b4 +*) = 121a10 − 9b8

Mathematics
1 answer:
natita [175]2 years ago
6 0
The answer for this is (-3b4) (3b4 +) = 121a10-9b8
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3 years ago
Some one please help !!! How do I solve -1<-x/3<1
MArishka [77]
- 1 < - x/3 < 1
1st. Multiply all parts by 3:

-3 < - 3x/3 < 3. Simplify the mid term:

-3 < -x <  3. Now multiply all terms by - 1. Note when you multiply by a negative number, you flip the inequality signs:

(-1)(-3) < (-1)(-x) < (-1)(3)

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You want to decorate your wording studio with famous record album covers. The rectangular region you want to decorate measures 7
GarryVolchara [31]

Answer:

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A=4536

Then find the area 12*12

A=144

Then divide 4536/144

You would need 31.5 12 by 12in covers to decorate the rectangular region

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As for the 9 by 9

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And as for the 15 by 15

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4 0
3 years ago
Not sure how I am supposed to arrive to an answer
ANEK [815]

Integrating both sides once gives

\dfrac{\mathrm d\mathbf r}{\mathrm dt}=2e^t\,\mathbf i+3e^{-t}\,\mathbf j+4e^{2t}\,\mathbf k+\mathbf c

where \mathbf c is an arbitrary constant vector. Use the initial condition to find its value:

\dfrac{\mathrm d\mathbf r}{\mathrm dt}(0)=-\mathbf i+7\,\mathbf j=(2+c_1)\,\mathbf i+(3+c_2)\,\mathbf j+(4+c_3)\,\mathbf k

\implies\mathbf c_1=-3\,\mathbf i+4\,\mathbf j-4\,\mathbf k

Integrate again:

\mathbf r(t)=2e^t\,\mathbf i-3e^{-t}\,\mathbf j+2e^{2t}\,\mathbf k+\mathbf c_1t+\mathbf c_2

where \mathbf c_2 is another arbitrary vector of constants. Use the other initial condition to determine its components:

\mathbf r(0)=6\,\mathbf i+\mathbf j+3\,\mathbf k=(2+c_1)\,\mathbf i+(-3+c_2)\,\mathbf j+(2+c_3)\,\mathbf k

\implies\mathbf c_2=4\,\mathbf i+4\,\mathbf j+\mathbf k

Then the particular solution to this ODE is

\boxed{\mathbf r(t)=(2e^t-3t+4)\,\mathbf i+(-3e^{-t}+4t+4)\,\mathbf j+(2e^{2t}-4t+1)\,\mathbf k}

5 0
3 years ago
Is 896,850 divisible by 9?<br><br> HELP ME PLZ!!!!
Papessa [141]

yes, since you need it know then take the asnwer and i'll explain later (:

7 0
3 years ago
Read 2 more answers
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