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Akimi4 [234]
3 years ago
15

1. The algebraic letter 'dy' stands for

Physics
1 answer:
VLD [36.1K]3 years ago
4 0
I think it’s the derivative of y
You might be interested in
Particles q1 = -53.0 uc, q2 = +105 uc, and
Nimfa-mama [501]

Answer:

-180.38\ \text{N}

Explanation:

q_1=-53\ \mu\text{C}

q_2=105\ \mu\text{C}

q_3=-88\ \mu\text{C}

r = Distance between the charges

r_{12}=0.5\ \text{m}

r_{23}=0.95\ \text{m}

r_{13}=1.45\ \text{m}

k = Coulomb constant = 9\times 10^9\ \text{Nm}^2/\text{C}^2

Net force is given by

F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}

The force on the particle q_1 is -180.38\ \text{N}.

8 0
3 years ago
Joe used a 750 watt 1/2" cordless drill to put together a bookcase. Calculate the work involved in this thirty minute process.
Nataliya [291]

750W 30mins...750x30x60 joules ... 75000x18 ... about 1,500,000j

D

3 0
3 years ago
Read 2 more answers
Which is written in scientific notation?
zaharov [31]

Answer:

<h2>C</h2>

Explanation:

2.0 × 10^3 is the correct form for writing any term in scientific notation form.

Comment for understanding anything.

7 0
3 years ago
if a car has a kinetic energy of 400 J at 20m/s what.is the cars kinetic energy in kJ at a speed of 5 m/s
Nutka1998 [239]

Kinetic energy is an expression of the fact that a moving object can do work on anything it hits; it quantifies the amount of work the object could do as a result of its motion. It can be calculated as:

 

KE = mv^2 /2

 

We calculate the problem as follows:

 

KE = mv^2 /2

400 = m(20)^2 / 2

<span>m = 2 kg</span>

8 0
3 years ago
At a rock concert, a dB meter registered 131 dB when placed 2.6 m in front of a loudspeaker on the stage. The intensity of the r
Pavlova-9 [17]

Answer:

Explanation:

A) 131 dB = 10*log(I / 1e-12W/m²)

where I is the intensity at 2.6 m away.

13.1 = log(I / 1e-12W/m²

1.25e13= I / 1e-12W/m²

I = 1.25 x10^1W/m²

power = intensity * area

P = I * A = 12.5W/m² * 4π(2.6m)² =1061 W ◄

B) 86 dB = 10*log(I / 1e-12W/m²)

8.6 = log(I / 1e-12W/m²)

3.98e8 = I / 1e-12W/m²

I = 3.98e-4 W/m²

area A = P / I = 1061W / 3.98e-4W/m² = 2.66e6 m²

A = 4πr²

2.66e6 m² = 4πr²

r = 14.5m ◄

6 0
3 years ago
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