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miss Akunina [59]
3 years ago
6

Which oLaw of Attraction Law of Inertia Law of Acceleration

Physics
1 answer:
o-na [289]3 years ago
3 0

Answer:

Newton's second law

Explanation: hopes this helps

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Musicians can use beats to tune their instruments. One flute is properly tuned and plays the musical note A at exactly 440 Hz. A
kodGreya [7K]

Answer:

439 Hz

Explanation:

f_1 = Frequency of first wave = 440 Hz

F = Beat frequency = 1 Hz

f_2 = Frequency of the instrument

The beat frequency is the difference of the two waves which are interacting with each other

F=f_1-f_2\\\Rightarrow 1=440-f_2\\\Rightarrow f_2=440-1\\\Rightarrow f_2=439\ Hz

The frequency of the instrument is 439 Hz

5 0
3 years ago
A child throws a baseball directly upward. What are the signs of the velocity and acceleration of the ball at the very top of th
Anastaziya [24]

Answer:

velocity zero and acceleration negative

Explanation:

According to the directions taken in the vector analysis, the direction which is upwards taken as positive, the direction which is downwards is taken as negative.

The direction which is rightwards taken as positive and the direction which is leftwards taken as negative.

here, ball throws vertically upwards and it attains a maximum height. At maximum height the magnitude of velocity is zero but the acceleration is always acting downwards so it is taken as negative in sign.

3 0
3 years ago
The "Hangtime" or time spent in the air by a projectile is dependent on
jekas [21]

Answer:

Density.

Explanation:

8 0
3 years ago
A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
Evaporation only occurs at the surface of a liquid
Veseljchak [2.6K]

yes

evaporation starts on the surface

8 0
4 years ago
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