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3 years ago

10 POINTS!!! WILL MARK BRAINLIEST

Mathematics

2 answers:

kvasek [131]3 years ago

8 0

Answer:

Step-by-step explanation:

75+3x+(4x+10)

ok look at the triangle 2 sides are congruent means 2 angles are congruent

that means that 75 and 3x are congruent

75=3x

divide by 3 both sides

x=25

75+75=150

30=4y+10

y=5

Naddik [55]3 years ago

4 0

I got it to be 2(2y+5)

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A parallelogram has vertices E(1, 4), F(5, 3), G(−3, 1), and H(1, 0). What are the coordinates of the midpoint of each diagonal?

kozerog [31]

Check the picture below.

now, the diagonals cut each other in two equal halves, thus, the midpoint of GF is the same coordinates as the midpoint for EH, so let's check what the midpoint for GF is then

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
G&({{ -3}}\quad ,&{{ 1}})\quad 
% (c,d)
F&({{ 5}}\quad ,&{{ 3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{5-3}{2}~~,~~\cfrac{5-1}{2} \right)\implies \left( \cfrac{2}{2}~~,~~\cfrac{4}{2} \right)\implies (1,2)$

5 0

3 years ago

14, 16, and 20 using elimination method showing work. Thanks so much

Nady [450]

14) x=0, y=3, z=-2

Solution Set (0,3,-2)

16) x=1, y=1 and z=1

Solution set = (1,1,1)

20) x = -263/31, y=164/31 ,z=122/31

Solution set (-263/31, 164/31 ,122/31)

Step-by-step explanation:

14)

$x-y+2z=-7\\y+z=1\\x=2y+3z$

Rearranging and solving:

$x-y+2z=-7\,\,\,eq(1)\\y+z=1\,\,\,eq(2)\\x-2y-3z=0\,\,\,eq(3)$

Eliminate y:

Adding eq(1) and eq(2)

$x-y+2z=-7\,\,\,eq(1)\\ 0x+y+z=1\,\,\,eq(2)\\-------\\x+3z=-6\,\,\,eq(4)$

Multiply eq(2) with 2 and add with eq(3)

$0x+2y+2z=2\,\,\,eq(2)\\\\x-2y-3z=0\,\,\,eq(3)\\--------\\x-z=2\,\,\,eq(5)$

Eliminate x:

Subtract eq(4) and eq(5)

$x+3z=-6\,\,\,eq(4)\\x-z=2\,\,\,eq(5)\\-\,\,\,+\,\,\,\,\,\,-\\---------\\4z=-8\\z= -2$

So, value of z = -2

Now putting value of z in eq(2)

$y+z=1\\y+(-2)=1\\y-2=1\\y=1+2\\y=3$

So, value of y = 3

Now, putting value of z and y in eq(1)

$x-y+2z=-7\\x-(3)+2(-2)=-7\\x-3-4=-7\\x-7=-7\\x=-7+7\\x=0$

So, value of x = 0

So, x=0, y=3, z=-2

S.S(0,3,-2)

16)

$3x-y+z=3\\\x+y+2z=4\\x+2y+z=4$

Let:

$3x-y+z=3\,\,\,eq(1)\\x+y+2z=4\,\,\,eq(2)\\x+2y+z=4\,\,\,eq(3)$

Eliminating y:

Adding eq(1) and (2)

$3x-y+z=3\,\,\,eq(1)\\x+y+2z=4\,\,\,eq(2)\\---------\\4x+3z=7\,\,\,eq(4)$

Multiply eq(1) by 2 and add with eq(3)

$6x-2y+2z=6\,\,\,eq(1)\\x+2y+z=4\,\,\,eq(3)\\---------\\7x+3z=10\,\,\,eq(5)$

Now eliminating z in eq(4) and eq(5) to find value of x

Subtracting eq(4) and eq(5)

$4x+3z=7\,\,\,eq(4)\\7x+3z=10\,\,\,eq(5)\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,-\\-----------\\-3x=-3\\x=-3/-3\\x=1$

So, value of x = 1

Putting value of x in eq(4) to find value of x:

$4x+3z=7\\4(1)+3z=7\\4+3z=7\\3z=7-4\\z=3/3\\z=1$

So, value of z = 1

Putting value of x and z in eq(2) to find value of y:

$x+y+2z=4\\1+y+2(1)=4\\1+y+2=4\\y+3=4\\y=4-3\\y=1$

So, x=1, y=1 and z=1

Solution set = (1,1,1)

20)

$x+4y-5z=-7\\3x+2y+2z=-7\\2x+y+5z=8$

Let:

$x+4y-5z=-7\,\,\,eq(1)\\3x+2y+2z=-7\,\,\,eq(2)\\2x+y+5z=8\,\,\,eq(3)$

Solving:

Eliminating z :

Adding eq(1) and eq(3)

$x+4y-5z=-7\,\,\,eq(1)\\2x+y+5z=8\,\,\,eq(3)\\---------\\3x+5y=1\,\,\,eq(4)$

Multiply eq(1) with 2 and eq(2) with 5 and add:

$2x+8y-10z=-14\,\,\,eq(1)\\15x+10y+10z=-35\,\,\,eq(2)\\----------\\17x+18y=-49\,\,\,eq(5)$

Eliminate y:

Multiply eq(4) with 18 and eq(5) with 5 and subtract:

$54x+90y=18\\85x+90y=-245\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\-------\\-31x=158\\x=-\frac{263}{31}$

So, value of x = -263/31

Putting value of x in eq(4)

$3x+5y=1\\3(-\frac{263}{31})+5y=1\\-\frac{789}{31}+5y=1 \\5y=1+\frac{789}{31}\\5y=\frac{820}{31}\\y=\frac{820}{31*5}\\y=\frac{164}{31}$

Now putting x = -263/31 and y=164/31 in eq(1) and finding z:

We get z=122/31

So, x = -263/31, y=164/31 ,z=122/31

Solution set (-263/31, 164/31 ,122/31)

Keywords: Solving system of Equations

Learn more about Solving system of Equations at:

#learnwithBrainly

4 0

3 years ago

5<br> 2. Simplify<br> .<br> 5<br> O 57<br> O 5-1<br> o<br> 5<br> O<br> 57

pantera1 [17]

Answer:

79853709 with the exponent of 94

Step-by-step explanation:

8 0

3 years ago

‐(5k – 3) ≤ 15 + 3k :) pls help

Juliette [100K]

Answer:

k≥-1.5

Step-by-step explanation:

-(5k-3) ≤ 15 + 3k

-5k+3 ≤15 +3k

+5k +5k

3≤15+8k

-15 -15

-12 ≤ 8k

divide both sides by 8

-1.5 ≤ k

or k≥-1.5

Hope this Helps!!!

3 0

3 years ago

Read 2 more answers

Simplify each expression.

Elina [12.6K]

Step-by-step explanation:

remember that x^-n means 1/(x^n).

x^a × x^b = x^(a+b)

x^a / x^b = x^(a-b)

(x^a)^b = x^(a×b)

(x×y)^n = x^n × y^n

so,

a^2 / a^-2 = a^(2 - -2) = a^4

and

b^-3 / b^2 = b^(-3 - 2) = b^-5 = 1/(b^5)

that means we have then :

(a^4 × b^-5)^2 = (a^4)^2 × (b^-5)^2 = a^8 × b^-10 =

= a^8 / b^10 = a⁸/b¹⁰

5 0

3 years ago