Answer:
if no one answers pic b cuz i got good luck
Step-by-step explanation:
Answer:
x = 30
Step-by-step explanation:
6x = 180
Hope it helps
Answer:
Step-by-step explanation:
First, the acceleration of gravity is -9.8m/s^2. This still works out since the formula uses 1/2 of it.
Hopefully you see where the other parts come from. Anyway, standard form of a quadratic is ax^2+bx+c=0. So this is almost there. You just need to subtract that 2.1 from both sides.
-4.9t^2+7.5t+-.3=0
Now with this, since it has taken into account the height that the ball was caught with that 2.1, you just need to find the 0s, which is what the quadratic equation does.
The quadratic equation is (-b±sqrt(b^2-4ac))/(2a) and we have a = -4.9, b = 7.5 and c = -.3. Remember you want to keep the signs. Now we just plug in.
(-b±sqrt(b^2-4ac))/(2a)
(-7.5±sqrt((-7.5)^2-4*-4.9*-.3))/(2*-4.9)
(-7.5±sqrt(56.25-5.88))/(.9.8)
(-7.5±sqrt(50.37))/(-9.8)
(-7.5±7.097)/(-9.8)
The plus or minus means there are two equations.
(-7.5+7.097)/(-9.8) and (-7.5-7.097)/(-9.8) So we will solve for both of these.
.04112 and 1.4895. That means these two times are when the ball is at 2.1 meters. One time on the way up and one time on the way down. We can safely assume that the other player catches the ball on the way down, so we want to use the second time, so 1.4895 seconds.
Answer:
15 units
Step-by-step explanation:
The distance between two points can be found using the following formula:

Given points:
(-7, 5) and (2, -7)
<u>where:</u>
- x₁ = -7
- x₂ = 2
- y₁ = 5
- y₂ = -7
Substitute these points into the formula and simplify:
![\sf d=\sqrt{(2-(-7))^2+((-7)-5)^2} \ \textsf{[simplify the radicand]}\\\\ d=\sqrt{(2+7)^2+(-12)^2} \ \textsf{[simplify]}\\\\d=\sqrt{(9)^2+(-12)^2} \ \textsf{[evaluate the power]}\\\\d=\sqrt{81+144} \ \textsf{[add]}\\\\d=\sqrt{225}\ \textsf{[simplify]}\\\\d=15](https://tex.z-dn.net/?f=%5Csf%20d%3D%5Csqrt%7B%282-%28-7%29%29%5E2%2B%28%28-7%29-5%29%5E2%7D%20%5C%20%5Ctextsf%7B%5Bsimplify%20the%20radicand%5D%7D%5C%5C%5C%5C%20d%3D%5Csqrt%7B%282%2B7%29%5E2%2B%28-12%29%5E2%7D%20%5C%20%5Ctextsf%7B%5Bsimplify%5D%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B%289%29%5E2%2B%28-12%29%5E2%7D%20%5C%20%5Ctextsf%7B%5Bevaluate%20the%20power%5D%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B81%2B144%7D%20%5C%20%5Ctextsf%7B%5Badd%5D%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B225%7D%5C%20%5Ctextsf%7B%5Bsimplify%5D%7D%5C%5C%5C%5Cd%3D15)
The distance between the two points is 15 units.
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