Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
About 6,000 Double check the answer i gave you.
I would have to say SAS because they give 2 sides and an angle. Also 3:4 because the one side is 3 and add 1 for 4, same for 30 and 40.
Answer:
Positive: Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is always greater than a negative decimal.
Negative: When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.
All of it put together (same text as above):
Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is ALWAYS greater than a negative decimal. When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.
Answer:
$4.02
Step-by-step explanation:
$10.10 - $6.08 = $4.02
