X^4 - 3x^2 + 2
= (x^2 - 1)(x^2 - 2)
Note that x^-1 is the difference of 2 squares:-
= (x + 1)(x - 1)(x^2 - 2) Answer
Answer:
C.47
Step-by-step explanation:
You want to plug in all the numbers which gives you 3^3+2(8)- -4. You do 3*3*3 which gives you 27. You then do 2(8) which gives you 16. So your problem now is 27+16- -4. 27+16 is 43 and being you are subtracting a negative, it turns to a positive. So your answer ends up being 47.
The slope is 7/3
Hope this helps
20 degrees; add up the given angles for the remaining angle
Answer:
Applying cosine theorem:
AB = sqrt(AC^2 + BC^2 - 2 x AB x BC x cosC)
= sqrt( 72^2 + 135^2 - 2 x 72 x 135 x cos(119deg))
= 181
Applying sine theorem:
BC/sinA = AB/sinC
=> sinA = BC x sinC/AB
=> A = arcsin(BC x sinC/AB)
= arcsin( 135 x sin(119deg)/181)
= 40.7 deg
Hope this helps!
:)
