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sp2606 [1]
3 years ago
10

What is the answer to X^4 -3x^2+2

Mathematics
2 answers:
ipn [44]3 years ago
6 0
X^4 - 3x^2 + 2
= (x^2 - 1)(x^2 - 2)
Note that x^-1 is the difference of 2 squares:-
= (x + 1)(x - 1)(x^2 - 2)   Answer
astraxan [27]3 years ago
4 0
I guess you want to find its roots (its zeros). If so then:

Le X = x²

X²-3X+2 = 0 Solve this quadratic equation:

X₁ = [-b+√(b² - 4.a.c)]/2a   and X₂ = [-b-√(b² - 4.a.c)]/2a  

X₁ = [+3+√(9-8)]/2   X₂ = [+3-√(9-8)]/2

X₁ = 4/2 = 2    and X₂ = 2/2 = 1

but X = x² , then:

x' = +√X₁  and x" = - √X₁; x"' = +√X₂  and x"" = -√X₂

x' = √2, x" = -√2; x'" = 1 and x"" = -1

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Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

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V_c=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

R - radius

Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

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V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

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Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

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3 years ago
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