The answer is 21! - hope it helps
Sounds to me as tho you are to graph 3x+5y<10, and that after doing so you are to restrict the shaded answer area created by the "constraint" inequality x≤y+1. OR x-1 ≤ y OR y≥x-1. If this is the correct assumption, then please finish the last part of y our problem statement by typing {x-y<=1}.
First graph 3x+5y = 10, using a dashed line instead of a solid line.
x-intercept will be 10/3 and y-intercept will be 2. Now, because of the < symbol, shade the coordinate plane BELOW this dashed line.
Next, graph y=x-1. y-intercept is -1 and x intercept is 1. Shade the graph area ABOVE this solid line.
The 2 lines intersect at (1.875, 0.875). To the LEFT of this point is a wedge-shaped area bounded by the 2 lines mentioned. That wedge-shaped area is the solution set for this problem.
You follow the rules for the quadratic formula, where
x= (-b +- √(b²-4ac) )/2a
Filling a, b and c in yields
x = (8 +- √(64-164) ) / 2 =>
x = (8 - √-100)/2 or x = (4 + √-100)/2
Well, √-100 = 10i, so then you simplify to the last answer, D:
x = 4-5i or x=4+5i
Base case: For 
, the left side is 2 and the right is 
, so the base case holds.
Induction hypothesis: Assume the statement is true for 
, that is
We want to show that this implies truth for 
, that
The first 
terms on the left reduce according to the assumption above, and we can simplify the 
-th term a bit:
so the statement is true for all 
.
Answer:
The problem was that she omitted 0 in-between 3 and 2
