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notsponge [240]
2 years ago
12

do you think theres anyway at all that Fernando and i could ever work it out. i am crazy in love wirh him and wish that he would

call me​
Mathematics
2 answers:
nikklg [1K]2 years ago
6 0

Answer:

I do. But keep in mind, sometimes things aren't meant to be. You may not see it now but you could be better off without him.

Vladimir [108]2 years ago
3 0

Answer:

there is a way. try working things out. talk to him listen to what he has to say and make him listen to you. try calling him. I'm in a situation like that with a girl. I'm in love with her but she doesn't love me. we dated 3 times but it didn't work out. I love her and wish she felt the same. but in your situation Fernando most likely does love you back just something happened that he doesn't think he can forgive you for.

Step-by-step explanation:

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Step-by-step explanation:

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Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17
Luden [163]

The larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

ax^2 + bx + c = 0

Then its roots are given as:

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The given quadratic equation is

y = -2.2x^2 + 63.5x - 17

now, the roots of the equation are

x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

#SPJ1

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Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
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Given the differential equation

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The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
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3 years ago
Erin had 55 stuffed bears. She took out her 7 favorite and equally divided the rest among her 3 sisters. How many bears did each
m_a_m_a [10]

Answer:

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Step-by-step explanation:

55-7= 48

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