Let Sagar has x, thus, Mukund has x + 50.
=> total amount = 15000
=> amount of Sagar + amount of Mukund = 15000
=> x + (x + 50)= 15000
=> 2x + 50 = 15000
=> 2x = 14950
=> x = 7475
Sagar has = x = 7475
Mukund has = x + 50 = 7525
Question:
The parallelogram shown below has an area of 40 units squared.
Find the missing base.
Answer:
See Explanation Below
Step-by-step explanation:
The question is incomplete as the diagram which shows the dimension of the parallelogram is not attached.
However, I'll give a general explanation on how to get the base of the parallelogram. If you follow this explanation, you'll get the right answer regarding your question.
The area of a parallelogram is calculated as thus.
Area = Base * Height
Given that the area = 40 units²
Let's assume the height of the parallelogram is 10 unit.
All you need to do is to plug in these values in the formula above..
Area = Base * Height becomes
40 = Base * 10
Divide both sides by 10
40/10 = Base * 10/10
4 = Base
Hence, Base = 4 units
Or take for instance the height is 5 units.
You'll still follow the simple steps as it is above.
Area = Base * Height becomes
40 = Base * 5
Divide both sides by 5
40/5 = Base * 5/5
8 = Base
Hence, Base = 8 units
R>-6
Please correct me if I’m wrong
Answer:
B. (-3, 5, 6)
Step-by-step explanation:
The system of equations is:
x + 3y - z = 6 ... (i)
4x - 2y + 2z = -10 ... (ii)
6x + z = -12 ... (iii)
The value of z in (iii) is;
z = -12 - 6x
Replacing z in (i) and (ii) gives:
x + 3y - (-12 - 6x) = 6 ... (i)
4x - 2y + 2(-12 - 6x) = -10 ... (ii)
Simplifying gives;
7x + 3y = -6 ... (i)
-8x - 2y = 14 ... (ii)
Multiplying (i) by 2 and (ii) by 3 gives;
14x + 6y = -12 ... (i)
-24x - 6y = 42 ... (ii)
Adding (i) and (ii) gives;
-10x = 30
x = -3
Replacing x = -3 in (i) gives;
7(-3) + 3y = -6
3y = 21 - 6
y = = 5
Replacing x = -3 in (iii) gives;
6(-3) + z = -12
z = -12 + 18 = 6