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Anettt [7]
3 years ago
11

A) Find the GCF B) Factor out the GCF C) What are the solutions?

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0

Answer:

A) GCF = b^{2}

B) b^{2}(3b + 10) = 0

C) b = 0, b = -10/3

Step-by-step explanation:

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Please answer this correctly
Amiraneli [1.4K]

Answer: The first one

Step-by-step explanation:

If you take a look at the light pink squares, you can count three on the top and three on the bottom. Therefore, when looking at it from the top, you’ll see the first one.

I hope you found my answer helpful! If you did, give it a five-star rating and a thanks! I would really appreciate it!

Even a brainliest if you feel like it! ;)

3 0
3 years ago
Read 2 more answers
Start at 125 create a pattern that subtracts 6 from each number
igor_vitrenko [27]
In this question, you are asked to make a pattern start with 125 with 6 less number each pattern. Then the pattern equation would be: 125-6x where x is determined by the position of the number.

The question doesn't specify how many numbers in the pattern that needs to be written but the pattern should be like this: 125, 119, 113, 107, 101, 95, 89, 83, 77
8 0
3 years ago
Solve for r and t:<br> 6r - 3t = 6<br> 6r + 8t = -16
MAVERICK [17]
Multiply the first equation with (-1)
you should get this

-6r + 3t = -6
6r + 8t = -16

start to eliminate

11t = -22

divide by 11

t = -2

substitute 

6r - 3(-2) = 6
6r + 6 = 6
6r = 6 - 6
6r = 0 
r=0
8 0
3 years ago
a gardener has 8 pounds of fertilizer. He packs the fertilizer into 5/8 pound bags. What is the maximum number of 5/8 pound bags
navik [9.2K]
A gardener has 8 pounds of fertilizer. He packs the fertilizer into 5/8 pound bags. What is the maximum number of 5/8 pound bags he can pack?

so first you multiply 8 pounds times 5 from 5/8 which is 40/8 pounds bags
now how many 8s can fit in 40 
40 divided by 8 =5 
so he can pack 5 maximum bags
7 0
3 years ago
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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