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OLEGan [10]
3 years ago
6

The horizontal axis in the sampling distribution of ModifyingAbove p with caret represents all possible sample proportions from

a simple random sample of size n. Bold (a )What percent of sample proportions results in a 99​% confidence interval that includes the population​ proportion? Bold (b )What percent of sample proportions results in a 99​% confidence interval that does not include the population​ proportion?
Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Answer: (a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.

(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

Step-by-step explanation:

(a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.

Explanation: If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals.

(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

Explanation: The 99% of the confidence intervals includes the population proportion value, it means, the remaining (100% – 99%) 1% of the intervals does not includes the population proportion.

If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals and 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

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Subtract - 2x - 10 from 10x2 + 3.
krok68 [10]

Answer:

10x2 + 2x + 13.

Step-by-step explanation:

10x2 + 3  - (-2x - 10)      (Note you have to put the -2x - 10 in brackets).

= 10x2 + 3 + 2x + 10      (Distributing the negative over the brackets).

= 10x2 + 2x + 13.

8 0
3 years ago
What is the product?
Wewaii [24]

Answer:

-30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2 ab^3

Step-by-step explanation:

6 0
2 years ago
The side lengths of a square measure 25.3 cm. Estimate the area of the square.
s2008m [1.1K]
Estimate, ok
area=side^2
if we round
25^2=625
25.3 is slighly bigger so maybe 632 squaer centimters or something
3 0
3 years ago
Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (
Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

(c) 209 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138    (1)

The second equation in the unknowns is

3B + 5N = 71  (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===>   40B + 30N = 690   (3)

Multiplying (2) by 6 ===>  18B + 30N = 426    (4)

(3) - (4) eliminates the N variables and yields

22B = 264   ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==>  36 + 5N = 71 ==> 5N = 71-36 = 35 ==>  N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

(c) If we add both equations (1) and (2), we get

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0
2 years ago
HELP PLEASE ANSWER ASAP 20 POINTS I NEED A CORRECT ANSWER
lina2011 [118]

Answer:

Equivalent factions

Step-by-step explanation:

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 89 and 56 is 1

Divide both the numerator and denominator by the GCD

89 ÷ 1

56 ÷ 1

Reduced fraction:  

89

56

Equivalent fractions: 178/112 267/168 445/280 623/392

More fractions: 178/56 89/112 267/56 89/168 445/56 89/280 623/56 89/392

7 0
3 years ago
Read 2 more answers
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