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OLEGan [10]
3 years ago
6

The horizontal axis in the sampling distribution of ModifyingAbove p with caret represents all possible sample proportions from

a simple random sample of size n. Bold (a )What percent of sample proportions results in a 99​% confidence interval that includes the population​ proportion? Bold (b )What percent of sample proportions results in a 99​% confidence interval that does not include the population​ proportion?
Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Answer: (a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.

(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

Step-by-step explanation:

(a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.

Explanation: If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals.

(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

Explanation: The 99% of the confidence intervals includes the population proportion value, it means, the remaining (100% – 99%) 1% of the intervals does not includes the population proportion.

If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals and 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

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Suppose you want to estimate the proportion of traditional college students on your campus who own their own car. From research
Lapatulllka [165]

Answer:

2,655 students

Step-by-step explanation:

The z-score for a 99% confidence interval is z = 2.576

The standard error for a proportion p is:

SE = z*\sqrt{\frac{p*(1-p)}{n} }

For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:

0.02 = 2.576*\sqrt{\frac{0.2*(1-0.2)}{n}}\\n=2,654.31

Rounding up to the next whole student, the sample size needed is 2,655 students.

5 0
3 years ago
Can someone help me with this question please?
Paladinen [302]
60 movies ------ 100%
9 movies -------- x%
__________________
60*x=9*100%
60x=900%   |:60
x=15%

The answer is 15%
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7 0
4 years ago
1 2 3 4 5 6 7 8 9 10
Elina [12.6K]

Answer:

(2x – 3)(5x^2 – 2x + 7)

=103−192+20−21

Hope This Helps!!!

4 0
3 years ago
What is the first step for solving the inequality 3y+14=44
uranmaximum [27]
3y+14=44

Answer: First step is to subtract 14 from each side

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3 years ago
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Lapatulllka [165]

Answer:2

Step-by-step explanation:

6 0
3 years ago
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