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Juli2301 [7.4K]
3 years ago
8

What is the value of (33 - 2 × 7) + (5 × 3 - 22) ?

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

12

Step-by-step explanation:

Keep in mind the rules of PEMDAS

P (parenthesis)

E (exponents)

M (multiply)

D (division)

A (addition)

S (subtraction)

Because parenthesis is the first operation in PEMDAS, you would start by calculating inside the parenthesis

We can start with the numbers inside the first parenthesis

(33 - 2 × 7)

Start by multiplying 2 and 7 because the M comes before the S

(33 - 2×7)= (33- 14)

Now subtract 14 from 33

(33-14) = 19

Step 2: Calculate inside the second parenthesis

(5 × 3 - 22)

Multiply first

(5 × 3 - 22)= (15 - 22)

Subtract!

(15 - 22)= -7

Now add the final number together

(why? There is an addition sign between the two parenthesis ordering us to add the final numbers together)

19 + (-7)

19-7

12

I hope this helps!!!

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Answer:

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<em>Comment on "the work"</em>

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3 years ago
(3-4i)(6i+7)-(2-3i)
Sergeu [11.5K]

Answer:

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Step-by-step explanation:

We are given the expression:

\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)}  \\  \displaystyle \large{[18i + 21  - 24 {i}^{2}  - 28i]- (2 - 3i)}

Now combine like terms.

\displaystyle \large{[ - 10i+ 21  - 24 {i}^{2} ]- (2 - 3i)}

<u>I</u><u>m</u><u>a</u><u>g</u><u>i</u><u>n</u><u>a</u><u>r</u><u>y</u><u> </u><u>U</u><u>n</u><u>i</u><u>t</u>

\displaystyle \large{i =   \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2}  =   - 1 }

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\displaystyle \large{[ - 10i+ 21  - 24  ( - 1) ]- (2 - 3i)}  \\   \displaystyle \large{[ - 10i+ 21   + 24]- (2 - 3i)}  \\   \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}

Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.

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Combine like terms.

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3 years ago
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