H(x)=-16t^2+300
The average rate is the change in h divided by the change in t, mathematically:
r=(h(3)-h(0))/(t2-t1), in this case:
r=(-16*9+300-0-300)/(3-0)
r=-144/3
r= -48 ft/s
Answer:
The tall of the flag pole is 51 ft answer (A)
Step-by-step explanation:
∵ The tall of the man = 6 ft
∵ The his shadow = 10 ft
∵ The shadow of the flag pole = 85 ft
∵ Tall of the man/tall of the flag = shadow of the man/shadow
of the flag
∴ 6/x = 10/85 ⇒ where x is the tall of the flag
∴ x = (6 × 85) ÷ 10 = 510 ÷ 10 = 51 ft
∴ The tall of the flag pole is 51 ft
You would set it up: .5/100 = x/490 and then cross multiply .5 time 490 and 100 times x, and end up with: 245=100x. divide by 100, and get 2.45
There are 5280 feet in a mile:
5280ft/mi
When using proportions to solve for unknown quantities, you need to keep the same units on the same side. This means keep "ft" on the top side and "mi" on the bottom side.
I would go with the second choice.