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3 years ago

Which statement describes the congruent triangles?

Mathematics

2 answers:

larisa86 [58]3 years ago

8 0

Answer:

Triangle W X Z is congruent to triangle Z Y X

Step-by-step explanation:

2 triangles are said to be congruent when all the corresponding sides of the angle and the interior angles are congruent .The two triangle are said to be the mirror image of each other.

In the simple case above the two triangles WXZ and ZYX are congruent because every corresponding side has the same length, and every corresponding angle has the same measure.

Vika [28.1K]3 years ago

5 0

Answer:

its acctually Triangle W X Z is congruent to triangle Y Z X

Step-by-step explanation:

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Pls help me figure out the slope

cluponka [151]

Answer:

$m=\frac{-4}{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (-3, 1)

Point (2, -3)

Step 2: Find slope m

Substitute: $m=\frac{-3-1}{2+3}$
Subtract/Add: $m=\frac{-4}{5}$

7 0

3 years ago

Which inequality can be used to explain why these three segments cannot be used to construct a triangle?

ryzh [129]

The answer choice which explains that the three segments cannot be used to construct a triangle is; AC + CB < AB.

<h3>Which inequality explains why the three segments cannot be used to construct a triangle?</h3>

Since, It follows from the triangle inequalities theorem that sum of the side lengths of any two sides of a triangle is greater than the length of the third side.

Hence, since the sum of sides AC + CB is less than AB, it follows that the required inequality is; AC + CB < AB.

Read more on triangle inequalities;

brainly.com/question/309896

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7 0

1 year ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$