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Liula [17]
4 years ago
8

How to solve a system of equations by substitution

Mathematics
1 answer:
kirill115 [55]4 years ago
4 0
First, substitute y in 3x-2y=9 for what it says y equals (2x-7). You now have: 3x-2(2x-7)=9. Breakdown:
3x-2(2x-7)=9
3x-4x+14=9
-1x=-5
x=5
next solve for y
y=2x-7
y=2(5)-7
y=10-7
y=3
<span>So Now We Have x=5, and y=3.
</span>Hope That Helped =D
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Answer:

(a)n^{th} = n

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Step-by-step explanation:

(a) This is a sequence of consecutive number

n^{th} = n

f(1) = 1

f(n) = f(n-1) + 1

(b) This is a sequence of 2 to the power of n - 1. The next number is twice time of this number

n^{th} = 2^{n-1}

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f(n) = f(n-1) * 2

(c) This is factorial sequence. Where the next number is this number multiplied by n^{th}

n^{th} = n!

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f(n) = f(n-1) * n

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Step-by-step explanation:

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