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mixas84 [53]
3 years ago
13

If f(x) = 4x2 and g(x) = x+1, find (f•g)(x).​

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

Hey there! The answer to your question will be below.

Step-by-step explanation:

The answer to your question is 4x^3 + 4x^2 or 3x² +6

I attached a picture sorry for my handwriting

( it only says 3x²+6 but I meant to say both 4x^3 + 4x^2 or 3x² +6)

Hope that helps

By: xBrainly

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Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6
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Each curve completes one loop over the interval 0\le t\le2\pi. Find the intersections of the curves within this interval.

6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi

The region of interest has an area given by the double integral

\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta

equivalent to the single integral

\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta

which evaluates to 9\pi+72.

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Shontell spends $7 a month plus $0.10 per minute. Determine whether the cost per month is proportional to the to the number of m
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Equation is 0.1x + 7

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PLEASE HELP
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What is the domain of the set of ordered pairs above

c {-1 ,0, 5, 10}

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3 years ago
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Kamila [148]

Answer:

30 %

Step-by-step explanation:

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3 years ago
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How do you solve this??? I need it fast please help with steps.<br> (x+3)(x+1)^2(x−4)&gt;0
scZoUnD [109]

Answer:

  x < -3 or x > 4

Step-by-step explanation:

The product of the factors is 4th-degree, and the leading coefficient is 1 (positive).

The factors tell you the following about the zeros:

  x = -3 . . . sign change from + to -

  x = -1 . . . graph touches, but no sign change. - on either side of x=-1

  x = 4 . . . sign change from - to +

__

The function will be positive for x < -3 and for x > +4.

_____

<em>Additional comments</em>

The value of the function is zero when any of its factors is zero. The value of a factor changes sign when the value of x changes from one side of the 0 to the other. For example, here, we have x+1 as a factor, so x=-1 is a zero. When x = -0.9, the factor is positive (-0.9 +1 = 0.1). When x = -1.1, the factor is negative (-1.1 +1 = -0.1). If this factor were to the first power, it would cause the value of the function to change sign at x=-1.

However, the factor (x+1) has an even power: (x+1)^2. That means when the factor is negative, its square is positive, and when the factor is positive, its square is positive. In short, the factor (x+1)^2 causes the function to be zero at x=-1, but does not make the function change sign there.

The product of all of these factors will result in a polynomial with x^4 as the highest-degree term. That means the function is of even degree. The leading coefficient is 1, so is positive, and the function will generally have a U-shape. The left-most (odd-degree) zero will be where the function changes sign from positive to negative. The right-most (odd-degree) zero will be where the function changes sign from negative to positive. Those zeros are x=-3 and x=+4, respectively. There are no places between these where the function changes sign, so these zeros are the ends of the regions where the function is positive (>0).

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2 years ago
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