Answer:
The probability that a call last between 4.2 and 4.9 minutes is 0.4599
Step-by-step explanation:
Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

We will use
, the cummulative distribution function of W. The values of
are well known and the can be found in the attached file

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599
Answer:
$34.78
Step-by-step explanation:
first, we need to find the value of 1 HCF, so we divide $48.70 by 14, giving us the result of 3.47857143. (rounding that turns out to be 3.48.
next, we need to multiply the cost of 1 HCF by 10, so 3.48 * 10 = 34.78
340 sq in. because (10*10=100) (10*12/2=60) (4*60=240) (((240+100=340)))
Answer:

Step-by-step explanation:
we know that
The triangle HPY is a right triangle (because the angle ∠HYP is a right angle)
Applying the Pythagorean Theorem
substitute the given values
Solve for HY

First slot, 11 options
2nd is 10 (1 less than 1st slot)
3rd is 9
4th is 8
11*10*9*8=7920 different pizzas (assuming you can't order all 1 topping)