Taking point (0,-2) of graph one and replacing in the equation;
2x+3y=6
2(0)+3(-2)=6
-6=6
So graph isn't the required graph.
Taking point (0,2) of graph 2;
2x+3y=6
2(0)+3(2)=6
6=6
So, graph 2 is the required graph.
Answer:
Solution in photo
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
f(x) = 2x^2 + 3
f(-3) = 2(-3)^2 + 3
f(-3) = 2(9) + 3
f(-3) = 18 + 3
f(-3) = 21
Step-by-step explanation:
Bc is also 20 answer is 400
