Answer is: volume is 25.08 liters.
Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂(g).
m(Na) = 51.5 g; mass of sodium.
n(Na) = m(Na) ÷ M(Na).
n(Na) = 51.5 g ÷ 23 g/mol.
n(Na) = 2.24 mol; amount of sodium.
From chemical reaction: n(Na) : n(H₂) = 2 : 1.
n(H₂) = 2.24 mol ÷ 2.
m(H₂) = 1.12 mol; amount of hydrogen gas.
V(H₂) = n(H₂) · Vm.
V(H₂) = 1.12 mol · 22.4 L/mol.
V(H₂) = 25.08 L; volume of hydrogen gas.
Answer:
As with any heat pump, geothermal and water-source heat pumps are able to heat, cool, and, if so equipped, supply the house with hot water. Some models of geothermal systems are available with two-speed compressors and variable fans for more comfort and energy savings.
Answer:
a. 0.18 mol
b. 1.084 x 10²³ atoms
Explanation:
Data Given:
mass of gold (Au) = 35.12 g
a. number of moles of gold (Au) = ?
b. number of atoms of gold (Au) =?
Solution:
Part a:
To find number of moles following formula will be used
no. of moles = mass in grams / molar mass . . . . . . (1)
molar mass of gold (Au) = 197 g/mol
put values in equation 1
no. of moles = 35.12 g / 197 g/mol
no. of moles = 0.18 mol
so. number of moles of Au = 0.18 mol
_________________
Part b:
To find number of atoms following formula will be used
no. of moles = no. of atoms / Avogadro's number
Rearrange the above equation
no. of atoms = no. of moles x Avogadro's number . . . . . . . (2)
Avogadro's number = 6.022 x 10²³ atoms /mol
put values in equation 1
no. of atoms = 0.18 mol x 6.022 x 10²³
no. of atoms = 1.084 x 10²³
so.
number of atoms of Au = 1.084 x 10²³ atoms
Answer:
ΔH of reaction is -147 kJ/mol
Explanation:
For the reaction:
CH₄(g) + X₂(g) → CH₃X(g) + HX(g)
It is possible to obtain ΔHr of reaction from the sum of ΔH of products minus ΔH of reactants:
ΔHr = ΔH CH₃X + ΔH HX - (ΔH CH₄ + ΔH X₂) <em>(1)</em>
The ΔH of each compound is obtained from bond energies thus:
ΔH CH₃X = 3×C-H + C-X = 3×416 kJ/mol + 222 kJ/mol = <em>1470 kJ/mol</em>
ΔH HX = H-X = <em>277 kJ/mol</em>
ΔH CH₄ = 4×C-H = 4×416kJ/mol = <em>1664 kJ/mol</em>
ΔH X₂ = X-X = <em>230 kJ/mol</em>
Replacing in (1):
ΔHr = 1470 kJ/mol + 277kJ/mol - (1664 kJ/mol + 230 kJ/mol) = <em>-147 kJ/mol</em>
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I hope it helps!