3. High tides and low tides are caused by the Moon. The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. ... When you're not in one of the bulges, you experience a low tide.
4. 1) As water warms and cools it expands and contracts; 2) The amount of water contained as ice on land surfaces changes over time; 3) The Earth's surface is dynamic and can move vertically. The first two reasons are directly caused by global temperature changes.
The full moon shows all of one side of the moon in pictures it is all white. In a new moon you can't see the moon cuz it's all dark and in pictures it is all black. Thus becoming opposites of each other.
Answer:
The answer is 1.06g.
Explanation:
Analysis of question:
1. Identify the information in the question given.
- volume of HCl is 2 dm3
- pH of HCl is 2.0
2. What the question want?
- mass of Na2CO3 is ?(unknown)
- 3. Do calculation.
- 1st-Write a balanced chemical equation:
Na2CO3 + 2HCl (arrow) 2NaCl + H20 + CO2
- 2nd-Determine the molarity of HCl with the value of 2.0.
pH= -log[H+]
2.0= -log[H+]
log[H+]= -2.0
[H+]= 10 to the power of negative 2(10-2)
=0.01 mol dm-3
molarity of HCl is 0.01 mol dm-3
- 3rd-Find the number of moles of HCl
n=MV
=0.01 mol dm-3 × 2 dm3
=0.02 mol of HCl
- 4th-Find the second mol of it.
Based on the chemical equation,
2.0 mol of HCl reacts with 1.0 mol of Na2CO3
0.02 mol of HCl reacts with 0.01 mol of Na2CO3
<u>N</u><u>a</u>2CO3>a=<u>1</u><u> </u>mol
<u>2</u><u>H</u>Cl>b=<u>2</u><u> </u>mol
mass= number of mole × molar mass
g=0.01 × [2(23)+ 12+ 3(16)]
g=0.01 × 106
# =1.06 g.
E= m× C2
... than:
m=E/c 2
m=1,366•10^3/3•10 A 8 2
m=1,518•10^14 kg
<u>3.04 </u> liters of propane(C₃H₈) are needed to react with 15.2 liters of oxygen to produce water and carbon dioxide
Explanation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
The mole ratio between the propane and oxygen in the equation is 1 : 5 as can be seen in the equation.
If the amount of O₂ reacting is 15.2 L then the amount of propane required is;
1 : 5
X : 15.2
We cross multiply the ration
5x = 15.2 * 1
X = 15.2/5
X = 3.04
= 3.04 L