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antiseptic1488 [7]
3 years ago
13

How would I graph this plz help me

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

Answer: [See attached immage]

EastWind [94]3 years ago
7 0

The Answer:    I really hope this helps!!!

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Mathhhh helppppppppppppppppppp
Salsk061 [2.6K]
4. C)If two figures are congruent, then they are similar.
If they are congruent them shape and size are the same and hence they are similar

5. Ratio 4/3 smaller side is 21
Multiply to find large side
4/3×21= 28ft D)

6. Width went from 24 to 3 in divide to get ratio
24/3 =8 now divide the length by 8 to find the postcard length
32/8= 4 in A)

8. If they are similar you need to find the ratio y reduces from 8 is similar to 6 so link those 6/8
This is your ratio you can simplify it to 3/4 now y/6 should also = 3/4
Y/6=3/4
Y=18/4= 4.5 C)

9.C)DC

8 0
3 years ago
Read 2 more answers
What are the following numbers from least to greatest 14/5, -2.46, -10/4, 2.5
Vera_Pavlovna [14]

Answer:

-2.46, -10/4, 14/5, 2.5.

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
castortr0y [4]

3. f(-6) = 12+1 =13


 f(-2) = 4+1 = 5


f(0) =1


Range {1,5,13}


4.  f(-2) = (-2)^3+1 =-7


  f(-1) = (-1)^2 +1 =0


f(3) = (3)^3 +1 = 28


Range = {-7,0,28}


5.the sequence is arithmetic


d= -11+19 = 8


an = a1 + d(n-1)


an = -19 +8(n-1)


6.l =w+5


a =l*w


a(w) =(w+5) * w


a(w)= w^2 +5w


f(w) = w^2 +5w


f(8) = 8^2 +5(8)


f(8) = 64 +40


f(8) =104 in^2



6 0
3 years ago
solve the given matrix equation for X. Simplify your answers as much as possible. (In the words of Albert Einstein, "Everything
vova2212 [387]

a.

XA^{-1}=A^3

(XA^{-1})A=A^3A

X(A^{-1}A)=A^4

X=A^4

b.

AXB=(BA)^2

A^{-1}(AXB)B^{-1}=A^{-1}(BA)^2B^{-1}

(A^{-1}A)X(BB^{-1})=A^{-1}(BA)^2B^{-1}

X=A^{-1}(BA)^2B^{-1}

c.

(A^{-1}X)^{-1}=(AB^{-1})^{-1}(AB^2)

X^{-1}A=(BA^{-1})(AB^2)

X^{-1}A=B(A^{-1}A)B^2

X^{-1}A=B^3

(XX^{-1})A=XB^3

XB^3=A

X(B^3(B^3)^{-1})=A(B^3)^{-1}

X=A(B^3)^{-1}

d. Not totally sure what the equation is supposed to be, but I guess it's

ABXA^{-1}B^{-1}=A

ABX(BA)^{-1}=A

((AB)^{-1}(AB))X((BA)^{-1}(BA))=(AB)^{-1}A(BA)

X=(AB)^{-1}A(BA)

X=(B^{-1}A^{-1})A(BA)

X=B^{-1}(A^{-1}A)(BA)

X=(B^{-1}B)A

X=A

7 0
3 years ago
The area of a rectangular dining room is 108ft squared and the length is 12ft. What is the width of the dining room?
Sveta_85 [38]

The width is 9.

Explanation: Because area is length times width, you need to divide area (108 ft) by length (12 ft) to get width. 108/12 is 9.

3 0
3 years ago
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