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3 years ago

If 3v/7 = 6then v = ? I’m not sure

Mathematics

2 answers:

Alex17521 [72]3 years ago

6 0

Answer:

v=14

Step-by-step explanation:

3v/7=6

x7 x7

3v=42

/3 /3

v=14

hope this helps:)

Mariulka [41]3 years ago

3 0

Step-by-step explanation:

3v/7=6

3v=6×7

3v=42

v=42/3

v=14

hope it helps.

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What is the value of this expression 4x^3y^2 when x=-1 and y=2

babunello [35]

The answer is -16. The picture is shown down below

6 0

3 years ago

Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad battery life. Batt

BartSMP [9]

Answer:

Null hypothesis: the variance in hours of usage for talking is not greater than the the variance in hours of usage for internet.

$H_o$ : $\sigma _1 ^2 \leq \sigma _2^2$

Alternative hypothesis: the variance in hours of usage for talking is greater than the the variance in hours of usage for internet.

$H_a : \sigma_1^2 > \sigma_2^2$

$\mathbf{s_ 1 =16.11}$

$\mathbf{s_2 = 7.98}$

Step-by-step explanation:

Let $x_1$ and $x_2$ be the two variables that represents the battery life in hours for talking usage and battery life in hours for internet usage respectively.

The hypothesis can be formulated as:

Null hypothesis: the variance in hours of usage for talking is not greater than the the variance in hours of usage for internet.

$H_o$ : $\sigma _1 ^2 \leq \sigma _2^2$

Alternative hypothesis: the variance in hours of usage for talking is greater than the the variance in hours of usage for internet.

$H_a : \sigma_1^2 > \sigma_2^2$

The standard deviation for the battery usage for talking is :

$\bar x_1 = \dfrac{1}{n_1} \sum x_i \\ \\ \bar x_1 = \dfrac{1}{12}(35.8 +22.4+...+35.5) \\ \\ \bar x_1 = \dfrac{241.2}{12} \\ \\ \bar x_1 =20.1$

The standard deviation Is:

$s_ 1 = \sqrt{\dfrac{1}{n_1-1}\sum (x{_1i}-\bar x_i)^2}$

$s_ 1 = \sqrt{\dfrac{1}{12-1}\sum (35.8- 20.1)^2+ (35.5-20.1)^2}$

$s_ 1 = \sqrt{259.568}$

$\mathbf{s_ 1 =16.11}$

The standard deviation for the battery life usage for the internet is :

$\bar x_2 = \dfrac{1}{n_2} \sum x_{2i}$

$\bar x_2 = \dfrac{1}{10} (24.0+12.5+36.4+...+4.7})$

$\bar x_2 = \dfrac{115}{10}$

$\bar x_2 = 11.5$

Thus; the standard deviation is:

$s_2 = \sqrt{\dfrac{1}{n_2-1}(x_{2i}- \bar x_2)^2}$

$s_2 = \sqrt{\dfrac{1}{10-1}(24-11.5)^2+(4.7-11.5)^2}$

$s_2 = \sqrt{63.60}$

$\mathbf{s_2 = 7.98}$

4 0

3 years ago

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It

Zanzabum

Answer: We reject H₀ we find that the machine is underflling the bottles

P ( 421 ± 4,3376 )

Step-by-step explanation:

We assume a normal distribution

Population mean 430 grs

Unknown standard deviation

We have a one tail condition "underfilling"

And our test is:

Null hypothesis H₀ X = μ₀

Alternative hypothesis Hₐ X < μ₀

We must use t student distribution and find the interval

X ± t*(s/√n)

In that expession X is the sample mean 421 grs, "s" is sample standard deviation, n is sample size, then

421 ± t * ( 15 / √21 ) (1)

We go to t table and look for t value for α = 0,1 and df = 21 - 1 df = 20

we get t (remember it is a one tail test) t = 1,325, plugging this value in equation (1) we get the interval

421 ± 1,325 * ( 15/√21 ) ⇒ 421 ± 1,325 * ( 3,2737)

421 ± 4,3376

421 + 4,3376 = 425,34

421 - 4,3376 = 416,66

As we can see the mean value of the population 430 grs is not inside the interval [ 416,66 ; 425,34 ] then we can assure the machine is underfilling the bags, and not meeting the setting spec

6 0

4 years ago

Needing help please.............

Margaret [11]

Use the formula y=mx+b

6 0

4 years ago

Find measure of angles B, E, D and C and the length of BC.

Angelina_Jolie [31]

Answer:

< B = 180-30-65=85°

< E = 85°

< D = 30°

< C = 65°

BC = 20/35 × 28 = 16

3 0

3 years ago

Read 2 more answers