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san4es73 [151]
3 years ago
11

Factorise 3(x-y)^2 - 2(x-y)

Mathematics
2 answers:
a_sh-v [17]3 years ago
8 0

Answer:

4xy

Step-by-step explanation:

Anna11 [10]3 years ago
4 0

Answer:

(x - y) [3(x - y) - 2]

Step-by-step explanation:

3(x - y)^{2}  - 2(x - y)

Lets take (x - y) common from the expression.

=> (x - y) [3(x - y) - 2]

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In the diagram below segment DEF is shown (since all three letters are shown, they are collinear). If
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Answer:

  • x = 4

Step-by-step explanation:

<u>Given</u>

  • DE = 3x + 2, EF = x + 5, DF = 23

<u>As per segment addition postulate</u>

  • DE + EF = DF

<u>Substituting values:</u>

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3 0
3 years ago
Express the complex number in trigonometric form. 5 - 5i
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               Hi my lil bunny!

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Lets do this step by step.

This is the trigonometric form of a complex number where |z| is the modulus and 0 is the angle created on the complex plane.

z = a + bi = |z| (cos ( 0 ) + I sin (0))

The modulus of a complex number is the distance from the origin on the complex plane.

|z| = \sqrt{a^2 + b^2} where z = a + bi

Substitute the actual values of a = -5 and b = -5.

|z| = \sqrt{(-5) ^2 + (-5) ^2}

Now Find |z| .

Raise - 5 to the power of 2.

|z| = \sqrt{25 + (-5) ^2}

Raise - 5 to the power of 2.

|z| = \sqrt{25 + 25}

Add 25 and 25.

|z| = \sqrt{50}

Rewrite 50 as 5^2 . 2 .

|z| = 5\sqrt{2}

Pull terms out from under the radical.

|z| = 5\sqrt{2}

The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion.

0 = arctan (\frac{-5}{-5} )

Since inverse tangent of  \frac{-5}{-5}  produces an angle in the third quadrant, the value of the angle is \frac{5\pi }{4} .

0 = \frac{5\pi }{4}

Substitute the values of 0 = \frac{5\pi }{4} and |z| = 5\sqrt{2} .

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Hope this helped you.

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