Answer:
9 / 64
Step-by-step explanation:
- In this task you have 2 events and you are looking for a joint probability. The first event is "Rebecca chooses a poodle". The probability of this event is:
P ( Rebecca chooses a poodle ) = 3 / 8
- because among 8 dogs there are 3 poodles.
- The second event is "Aaron selects a poodle".
This event has a probability of that is equivalent to previous selection:
P ( Aaron chooses a poodle ) = 3 / 8
- Because after Rebecca's choice the chosen poodle is replaced with the poodle; hence, there are 8 pets in total and among them there are 3 poodles.
- To calculate probability of both events ("Rebeca selects a poodle and Aaron selects a poodle") with replacement you have to multiply both calculated probabilities - condition of independent events :
P ( Aaron and Rebecca both select poodle ) = 3 / 8 * 3 / 8
= 9 / 64
In all of these cases, y=x+2.
There are two blue marbles so you have a 2/8 probability of drawing a blue marble on each draw since the marble is replaced after the first draw. 2/8 can be simplified to be 1/4 and then converted to be 0.25 per draw. 0.25 plus 0.25 equals 0.5. Since we are dealing with percentages multiply 0.5 x 100 which equals 50. Now take 50 and divided by the total number of marbles in the bag which is 8. 50 divided by 8 equals 6.25. So it would be about 6%.
