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Natasha_Volkova [10]
3 years ago
13

PLEASE HELP!!!! thank you if you help me!

Mathematics
2 answers:
ELEN [110]3 years ago
5 0

Answer:

i can see nothing

Step-by-step explanation:

stealth61 [152]3 years ago
5 0
I dont see anything its very glitching.
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Sue ran 7 miles more than Jill last week. Sue ran 11 miles. Which equation will tell you how many miles Jill ran?
Yuri [45]

Answer:

The number of miles Jill ran is the number of miles Sue ran (11) minus the number of miles Sue ran more than Jill (7).

So far, x=11-7.

Reorder the equation. Add 7 to both sides.

x + 7 = 11.

So, the correct equation is A.

:)

5 0
3 years ago
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Lynne used 3/8 cup of flour and 1/3 cup of sugar in a recipe.what number is a common denominator for3/8 and 1/3
Liula [17]

Ahiffggggggggggggt was the morning I was going over the

7 0
3 years ago
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PLEASE HELP!!
RSB [31]

Answer:

D.130°

Step-by-step explanation:

An arc measure ia an angle an arc makes with the circle's centre and is proportional to the angle it subtends to the circumference, arc length.

-Given that  AC and BC are diameters, then \angle AOB =\angle DOC since they are alternate angles.

\angle AOB =\angle dOC=180\textdegree\\\\3x-70=x+10\\\\x=40\textdegree

#Since angles on one side of a diameter sum up to 180°, mBC is calculated as:

(3x-70)+m\angle BC=180\\\\M\angle BC=180+70-3\times 40\\\\=130\textdegree

Hence, mBC=130°

3 0
3 years ago
If a new data point at 12 is added to the graph , which will be true ?
Orlov [11]

Answer:

3. The mean will increase more than median, but both will increase.

Step-by-step explanation:

We have been given a dot plot. We are asked to find the true statement, if a new data point at 12 is added to our given dot plot.

Since we know that an large valued outlier affects mean more than median, so mean will increase more than median.

Let us check this using our given information. Our data set before adding 12 is:

1, 2, 2, 2, 3, 4, 4, 4, 5.

We can see that our data set has odd number (9) of data points, so median will be the value of 5th term, that is 3.

\text{Mean}=\frac{1+2+2+2+3+4+4+4+5}{9}

\text{Mean}=\frac{27}{9}=3

Therefore, mean of our data set is 3.

Upon adding a data point at 12, our new data set will be:

1, 2, 2, 2, 3, 4, 4, 4, 5, 12.

Now our data set has 10 terms, so median will be the average of 5th and 6th term.

\text{Median}=\frac{3+4}{2}

\text{Median}=\frac{7}{2}=3.5

Therefore, the median of new data set will be 3.5.

\text{Mean}=\frac{1+2+2+2+3+4+4+4+5+12}{10}

\text{Mean}=\frac{39}{10}

\text{Mean}=3.9

Therefore, mean of new data set will be 3.9.

Upon looking at our given statements we can see that 3rd statement is true as mean and median both increased after adding 12 to our data set, but mean increased more that median. Mean and median before adding 12 was 3; but after adding 12 median became 3.5, while mean became 3.9 (which is greater than mean).



3 0
3 years ago
Read 2 more answers
Factorise x^2 + 10x + 16
tensa zangetsu [6.8K]
Answer:

(x + 2) (x + 8)

Explanation:

x^2 + 10x + 16
(x + 2) (x + 8)
7 0
3 years ago
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