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2 years ago

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2 answers:

elixir [45]2 years ago

5 0

Answer:

hope this helps you.

Carry on learning.

adoni [48]2 years ago

5 0

Explanation:

$hope \: its \: helpful \: to \: u$

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There will be 4 people chosen from a group of fifteen to fill four engineer positions at a local company. a. Does order count? b

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2 years ago

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2 years ago

If 384 ft of fencing is available and the maximum area is desired, what will be the dimensions of the larger, outer rectangle? (

DIA [1.3K]

The dimensions of the smaller holding pens from the parameters given are; 96 ft and 31 ft

<h3>What dimensions will maximize the area?</h3>

From the complete question, if the side lengths of the big rectangle are x and y, then the expression for the area A is:

A = x*y

Then perimeter since we have 384 ft of fencing available is;

2x + 2y = 384

y = (384 - 2x)/2

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Put 192 - x for y in area formula;

A = x(192 - x)

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This means that A is maximum at x - 96 = 0

Thus, A is maximum when x = 96 ft

At A_max; y = 192 - 96 = 96 ft

Since the area of the bigger rectangle has been maximized, it means that we have also maximized the area of the smaller pens. Therefore its' dimensions will be;

x_small = 96 ft/3 = 31 ft

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Read more about maximizing area at; brainly.com/question/9819619

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3 years ago