One may note, you never quite asked anything per se, ahemm, if you meant simplification.
Answer:
f(x) = 2x + 4 domains {-1, 0, 1}
range {2, 4, 6}
(please mark brain if this helps and is correct)
Step-by-step explanation:
to solve f(x) to find the range you would want to input all the domain numbers in the equation f(x) to get the range of all the numbers you need
step 1: take the first domain number and input it into your equation where x is
ex: 2x + 4 [2(-1) + 4] = -2 + 4 = 2
step 2: add the second domain number and input it into your equation where x is
ex: 2x + 4 [2(0) + 4] = 0 + 4 = 4
step 3: add the last domain number and input it into your equation where x is
ex: 2x + 4 [2(1) + 4] = 2 + 4 = 6
Now we have determined what the range is
Answer:
Step-by-step explanation: 7
Subtract 5 on both sides to get 4x = x + 21
then, subtract x from 4x and x is 1, so 3x = 21 then divide by 3 on both sides
f(0) = ( f(k) +f(-k) ) / 2
f(0) = (16 - 4) / 2
f(0) = 12 / 2
f(0) = 6 → ANSWER
*Remember that f(0) = m(0) + n = n
If we have f(x) = mx + n, then:
f(k)= mk + n and f(-k)= -mk + n
If we add them:
f(k) + f(-k)
= mk + n -mk + n
= 2n
= 2f(0)
So we conclude that:
f(0) = [f(k) + f(-k)] / 2