I would convert into decimals it's easier to do then multiply 9/12*1 3/4 and if your teacher wants it into fractions convert it back
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lllllllll} \log_{\underline{10}}(10)=1&\implies &\underline{10}^1=10 ~~ \checkmark\\\\ \log_{10}(100)=2&\implies &10^2=100~~ \checkmark\\\\ \log_{10}(55)=1.5&\implies &10^{1.5}=55\implies 10^{\frac{3}{2}}=55\implies \sqrt[2]{10^3}=55\\\\ &&\sqrt{1000}\ne 55 ~~ \bigotimes \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Blllllllll%7D%20%5Clog_%7B%5Cunderline%7B10%7D%7D%2810%29%3D1%26%5Cimplies%20%26%5Cunderline%7B10%7D%5E1%3D10%20~~%20%5Ccheckmark%5C%5C%5C%5C%20%5Clog_%7B10%7D%28100%29%3D2%26%5Cimplies%20%2610%5E2%3D100~~%20%5Ccheckmark%5C%5C%5C%5C%20%5Clog_%7B10%7D%2855%29%3D1.5%26%5Cimplies%20%2610%5E%7B1.5%7D%3D55%5Cimplies%2010%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%3D55%5Cimplies%20%5Csqrt%5B2%5D%7B10%5E3%7D%3D55%5C%5C%5C%5C%20%26%26%5Csqrt%7B1000%7D%5Cne%2055%20~~%20%5Cbigotimes%20%5Cend%7Barray%7D)
increments over the exponent, are not directly proportional to increments on the resulting values, namely the half-way from 10² and 10⁴ is not 10³, because 10⁴ is 100 times 10², and 10³ is simply 10 times 10².
Answer:

Step-by-step explanation:
a trinomial that cannot be factored has no real roots.
here is one:

After graphing this trinomial has no intersections points with the x-axis wich means it has no roots
Answer:
In your equation, put 3 where x is, and -1 where y is. If you get a true statement, like -8 = -8, or 69 = 69, then (3, -1) is a solution. If you get a false statement, like 9 = 21 or 10 = 420, then (3, -1) is not a solution.